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kompoz [17]
3 years ago
13

A cat that weighs 55 N sits on the top of a cat tree. It is 2 m above a 110 N

Physics
2 answers:
GuDViN [60]3 years ago
7 0

Answer:

<u>Answer</u><u>:</u><u> </u><u>B. The 55 N cat has less mass than the 110 N dog.</u>

• weight = mass × acceleration

<u>→</u><u> </u><u>For</u><u> </u><u>the</u><u> </u><u>cat</u>

{ \tt{55 = m _{cat} \times 10}} \\  \\ { \tt{m _{cat}  = 5.5 \:  kg }}

<u>→</u><u> </u><u>for</u><u> </u><u>the</u><u> </u><u>dog</u>

{ \tt{110 = m _{dog}  \times 10}} \\  \\ { \tt{m _{dog}  = 11 \: kg}}

Therefore:

{ \bf{m _{cat} < m _{dog} }}

Dominik [7]3 years ago
3 0
  • Take g=10m/s^2

Cat:-

\\ \sf\longmapsto F=ma

\\ \sf\longmapsto Mass=\dfrac{55}{10}=5.5kg

Dog:-

\\ \sf\longmapsto Mass=\dfrac{110}{10}=11kg

Option B is correct (Verified above)

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1.64 * 10^(-5) m

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