Answer:
(A.)Nuclear fission and beta decay (electron emission)
Lipids and <span>Polysaccharides r the answers hoped i helped</span>
The reverberation time with 800 audiences is 0.875 seconds.
<h3>
Reverberation time with 800 audience</h3>
R₁V₁ = R₂V₂
where;
- R₁ is the reverberation time with 400 audience
- R₂ is the reverberation time with 800 audience
- V₁ is initial volume
- V₂ is final volume
R₂ = R₁V₁/V₂
R₂ = (1.4 x 500) / 800
R₂ = 0.875 seconds
Thus, the reverberation time with 800 audiences is 0.875 seconds.
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Answer:
W_net = mg + 2mgh/r
Explanation:
The forces applied in this motion of the bowling ball are both gravitational and centripetal forces.
Now, gravitational force is; F_g = mg
While centripetal force is; F_c = mv²/r
Since we want to express the net force in terms of the variables in the statement and we are not given "v", let's find an expression of v with the variables given.
Now, from Newton's equation of motion, at initial velocity of 0, v² = 2gh.
Thus;
F_c = 2mgh/r
Where;
m is ball mass
r is tube radius
h is fall height
Thus, the net force will be;
F_net = F_g + F_c
Now, Net force would be equal to the net weight that will be read on the scale.
Thus;
W_net = F_net = F_g + F_c
W_net = mg + 2mgh/r
