Answer:
x = 0.81 m
Explanation:
given,
spring constant, k = 769 N/m
Potential energy of the spring = 250 J
distance of spring compression = ?
using conservation of energy
potential energy will equal to the spring energy
x² = 0.650
x = 0.81 m
Hence, the spring is compressed to 0.81 m
When the ion concentrations in the cathode half-cell are increased by a factor of 10, the change in the cell voltage is ln10 times greater. This comes from the Nernst equation. Use variation to solve for the cell voltage in terms of the initial cell voltage before increasing the ion concentrations by 10.
504000000=5.04*10^8
so in metric prefixes it will be
504 mega seconds or 5.04*10^2 mega seconds or 0.504 giga seconds
