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scZoUnD [109]
3 years ago
15

I need help asap on how to do this​

Mathematics
1 answer:
Anika [276]3 years ago
7 0

Answer:

me dont know

Step-by-step explanation:

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Jeremy is driving to his friends house that is 60 miles away from his home the scale on Jeremy's map is 1 1/2 inches equivalent
defon

Answer:

The distance between their house on the map is 10 inches.

Step-by-step explanation:

In order to calculate the distance from Jeremy's friend house to his we can apply a rule of three in a way that 60 miles is related to "x" inches in the same proportion as "1 1/2" inches is related to 9 miles. Before applying that it'll be for the best if we convert the mixed fraction to a pure fraction as shown below:

d = 1\frac{1}{2} = 1 + \frac{1}{2} = \frac{2}{2} + \frac{1}{2} = \frac{3}{2}

Creating the rule of three:

\frac{60}{9} \frac{\text{miles}}{\text{miles}} = \frac{x}{\frac{3}{2}} \frac{\text{inches}}{\text{inches}}\\\\9*x = \frac{60*3}{2}\\\\x = \frac{180}{18}\\\\x = 10 \text{ inches}

The distance between their house on the map is 10 inches.

3 0
3 years ago
I think the answe is c can somebody help me out ?
Alekssandra [29.7K]
Answer:
angle V = 60 degrees
angle U = 90 degrees
angle W = 30 degrees
This is the last option

Explanation:
Part a: getting angle U:
Let's start by doing the Pythagorean check:
hypotenuse = sqrt [(side1)^2 + (side2)^2]
side1 = 3√3 and side2 = 3 cm
Substitute in the above equation:
hypotenuse = sqrt [ (3√3)^2 + (3)^2]
hypotenuse = 6 cm
This proves that the given triangle is right-angled at U
Therefore:
measure angle U = 90 degree

Part b: getting angle V:
cos theta = adjacent / hypotenuse
theta is angle V
adjacent side = 3 cm
hypotenuse = 6 cm
Therefore:
cos V = 3/6 = 1/2
V = 60 degrees

Part c: getting angle W:
We can get this using two methods:
Method 1:
Angles of triangle = 180
180 = 90 + 60 + angle W
angle W = 180 - (90+60) = 30 degrees
Method 2:
cos theta = adjacent / hypotenuse
theta is W
adjacent = 3√3 cm
hypotenuse = 6 cm
Therefore:
cos W = 3√3 / 6 = √3 / 2
W = 30 degrees

Hope this helps :)
5 0
4 years ago
Find sec theta if theta is in quadrant 4 and sin theta= -1/5
lara31 [8.8K]

Answer:

\frac{5}{2\sqrt{6} }

Step-by-step explanation:

Since Θ is in fourth quadrant then cosΘ > 0, as is secΘ

Given

sinΘ = - \frac{1}{5}, then

cosΘ = \sqrt{1-(-1/5)^2}

         = \sqrt{1-\frac{1}{25} } = \sqrt{\frac{24}{25} } = \frac{2\sqrt{6} }{5}

Hence

secΘ = \frac{1}{\frac{2\sqrt{6} }{5} } = \frac{5}{2\sqrt{6} }

5 0
3 years ago
Read 2 more answers
Solve 15 ≥ -3x or 2/5x ≥-2<br> {x | x ≤ -5}<br> {all reals}<br> {x | x ≥ -5}
julia-pushkina [17]

Answer: x ≥ -5

Step-by-step explanation:  the 15 ≥ 3x is  x ≥ -5 and  2/5x ≥-2 =x ≥ -5

8 0
3 years ago
Read 2 more answers
Hellllllllllllllppppppppppppppppppppppppppppp
strojnjashka [21]

Answer:

c

Step-by-step explanation:

30/5=6 4*6= 24

6 0
3 years ago
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