Answer:
7) Decay
8) Growth
9) Growth
10) Growth
Step-by-step explanation:
7) As <em>x </em>increases, <em>y </em>is decreasing because as you add more value to the exponent, 1/3 gets smaller and smaller.
8) As <em>x </em>increases, <em>y </em>is increasing because as you add more value to the exponent, 2 gets bigger and bigger.
9) As <em>x </em>increases, <em>y </em>is increasing because as you add more value to the exponent, 2 gets bigger and bigger.
10) As <em>x </em>increases, <em>y </em>is increasing because as you add more value to the exponent, 2 gets bigger and bigger.
Step-by-step explanation:
you know that QPS adds up to 47
so the sum of RPS and QPR shoukd = 47
(3x - 38) + (7x - 95) = 47
you then solve for x then you can use that to find QPR
Answer:
14,146 years
Step-by-step explanation:
The annual multiplier is (1 -0.0049%) = 0.999951. We want to find the number of times this needs to be multiplied to make the product 1/2.
0.5 = 0.999951^t
log(0.5) = t·log(0.999951)
log(0.5)/log(0.999951) = t ≈ 14,145.514
The half-life is about 14,146 years.
(a) By the fundamental theorem of calculus,
<em>v(t)</em> = <em>v(0)</em> + ∫₀ᵗ <em>a(u)</em> d<em>u</em>
The particle starts at rest, so <em>v(0)</em> = 0. Computing the integral gives
<em>v(t)</em> = [2/3 <em>u</em> ³ + 2<em>u</em> ²]₀ᵗ = 2/3 <em>t</em> ³ + 2<em>t</em> ²
(b) Use the FTC again, but this time you want the distance, which means you need to integrate the <u>speed</u> of the particle, i.e. the absolute value of <em>v(t)</em>. Fortunately, for <em>t</em> ≥ 0, we have <em>v(t)</em> ≥ 0 and |<em>v(t)</em> | = <em>v(t)</em>, so speed is governed by the same function. Taking the starting point to be the origin, after 8 seconds the particle travels a distance of
∫₀⁸ <em>v(u)</em> d<em>u</em> = ∫₀⁸ (2/3 <em>u</em> ³ + 2<em>u</em> ²) d<em>u</em> = [1/6 <em>u</em> ⁴ + 2/3 <em>u</em> ³]₀⁸ = 1024
Y-y1=m(x-x1) is the point slope formula. m=3/4 and y1=-8 and x1=5. Substitute these values and you will have the answer.
