1. First, do 12 x 8 to work out the area of the rectangle, which is 96ft.
Then, to work out the area of a circle, you use the equation πr² to help you. You would multiply π by the radius², which is 16. Now you have just worked out the area of a circle, but not a semicircle, so you would have to divide your answer by two to get the area of this, which would be 25.13 (rounded to 2 d.p).
To get the area of the whole shape, you just have to add the two totals together. 
25.13 + 96 = 121.13ft.
Remember to put the units there, or you can lose marks.
Try your best with the next questions! I have written the formulas for the other shapes to help you work out the answers.
Area of a square = Multiply sides together.
Area of rectangle = Multiply width by length.
Area of a circle = Multiply π by the radius².
Area of a semicircle = Multiply π by the radius², and the divide by two.
Area of a triangle = Multiply the base by the height, and then divide by two.
Really hope this helps!
        
                    
             
        
        
        
Answer:a
Step-by-step explanation:
Cause boys is 2/5 and girls are 3/5
 
        
                    
             
        
        
        
Answer:
See attached
Step-by-step explanation:
The answer is in below picture
 
        
             
        
        
        
Answer: 7 times p 
the product of 7 and p
7 multiplied by p
Step-by-step explanation: anything that has to do with multiplying the two is correct
 
        
             
        
        
        
The required plane Π contains the line 
L: (-1,1,2)+t(7,6,2)
means that Π is perpendicular to the direction vector of the line L, namely
vl=<7,6,2>
It is also required that Π be perpendicular to the plane
Π 1 : 5y-7z+8=0
means that Π is also perpendicular to the normal vector of the given plane, vp=<0,5,-7>.
Thus the normal vector of the required plane, Π can be obtained by the cross product of vl and vp, or vl x vp:
 i  j  k
7 6  2
0 5 -7
=<-42-10, 0+49, 35-0>
=<-52, 49, 35> 
which is the normal vector of Π
Since Π has to contain the line, it must pass through the point (-1,1,2), so the equation of the plane is
Π :  -52(x-(-1))+49(y-1)+35(z-2)=0
=>
Π :  -52x+49y+35z = 171
Check that normal vector of plane is orthogonal to line direction vector
<-52,49,35>.<7,6,2>
=-364+294+70
=0   ok