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AURORKA [14]
2 years ago
14

A, B & C lie on a straight line.

Mathematics
1 answer:
VikaD [51]2 years ago
4 0

Answer:

Step-by-step explanation:

A, B & C lie on a straight line.

D, C & E lie on a different straight line.

Ah, this is 2 intersecting lines

angles

y

= 106° and angle

z

= 64°.

well we know that a full size of circle is 360 degrees

let's add z and y :

106+64 = 170

then, let's subtract it from 360

360 - 170 = 90

we must devide it by 2, why? because 90 is from two section of x (2x)

so 90/2 = 45

and there you have it x = 45

if you still cannot visualize what is intersecting line mean, then see the file below

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70% of 600 of what number?
ASHA 777 [7]

Answer:

number = 420

Step-by-step explanation:

70% * 600 =  number

.70 * 600 = number

420 = number

5 0
3 years ago
Mei likes to make desserts for bake sales. Last month, she made 2 batches of brownies and 3 batches of cookies, which called for
tino4ka555 [31]

Answer: she uses 2 eggs for one batch of brownies and 4 eggs for one batch of cookies.

Step-by-step explanation:

Let x represent the number of eggs that she uses for one batch of brownies.

Let y represent the number of eggs that she uses for one batch of cookies.

Last month, she made 2 batches of brownies and 3 batches of cookies. This means that

2x + 3y = 16 - - - - - - - - - -1

The month before, she baked 1 batch of brownies and 1 batch of cookies, which required a total of 6 eggs. This means that

x + y = 6 - - - - - - - - - - - - - 2

Multiplying equation 1 by 1 and equation 2 by 2, it becomes

2x + 3y = 16

2x + 2y = 12

Subtracting, it becomes

y = 4

Substituting y = 4 into equation 2, it becomes

x + 4 = 6

x = 6 - 4 = 2

7 0
3 years ago
Can someone help me with percents ?
denpristay [2]
The person HAD homework 75/100 or 75%

the remaining days he did NOT have homework , which is 25/100 or 25%
8 0
3 years ago
Read 2 more answers
List multiples of 6 between 20 and 50.​
xenn [34]

Answer:

6,12,18,24,30,36,42,48,54,69

5 0
3 years ago
Read 2 more answers
The researchers are concerned that the dollars spent per shopper examined in the study is too different from what has been found
Katarina [22]

Answer:

Step-by-step explanation:

Hello!

To study if the average dollars spend per shopper is different than the expected population average of $84.5 there was a sample of 120 shoppers taken and their spending habit registered.

Then the study variable is:

X: Amount of money spent by a shopper ($)

This population standard deviation is σ= $16

Using the data information I've run a normality test, with p-value: 0.3056 against the test significance level α: 0.05, the decision is to not reject the null hypothesis so there is enough statistical evidence to conclude that the study variable has a normal distribution.

X~N(μ;σ²)

I've also calculated the sample mean and standard deviation:

X[bar]= $81.01

S= $19.62

a.

If the objective is to test that the true mean spending for the population is significantly different than the expected average of 84.5, the parameter of interest is the population mean μ and the hypothesis test will be two-tailed.

H₀: μ = 84.5

H₁: μ ≠ 84.5

α:0.05

The statistic is a standard normal for one sample:

Z= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } } ~N(0;1)

Z_{H_0}= \frac{81.01-84.5}{\frac{16}{\sqrt{120} } } = -2.389

p-value two tailed  0.016894

b.

The decision rule using the p-value method is:

If p-value ≤ α ⇒ Reject the null hypothesis.

If p-value > α ⇒ Do not reject the null hypothesis.

Since the p-value is less than the significance level, the decision is to reject the null hypothesis.

c.

Using a level of significance of 5% the null hypothesis was rejected. So there is enough statistical evidence to support the researcher's claim that the true mean spending for the population is significantly different than the expected average of $84.5.

I hope it helps!

3 0
3 years ago
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