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rusak2 [61]
3 years ago
9

The solution to 2x -5=27 is also a solution of which of the following equations

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
4 0
X=16 

move constant to the right side and change its sign  2x=27(+5)
add the numbers  2x=32
x=16
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−14 + 6x + 7 − 2x = 1 + 5x<br> please answer this problem with work
maksim [4K]
Let's solve your equation step-by-step.<span><span><span><span><span>− 14 </span>+ <span>6x </span></span>+ 7</span> −<span> 2x </span></span>=<span> 1 + <span>5x</span></span></span>
Step 1: Simplify both sides of the equation.<span><span><span><span><span>−14 </span>+ <span>6x </span></span>+ 7 </span>− <span>2x </span></span>=<span> 1 +<span> 5x</span></span></span><span>
Simplify: </span><span><span><span>4x - </span><span>7 </span></span>= <span><span>5x</span> + 1</span></span><span><span><span>4x</span> − 7</span>= <span><span>5x </span>+ 1</span></span>
Step 2: Subtract 5x from both sides.<span><span><span><span>4x</span> − 7</span> − <span>5x </span></span>= <span><span><span>5x </span>+ 1</span> −<span> 5x</span></span></span><span><span><span>− x </span>− 7 </span>=1 </span>
Step 3: Add 7 to both sides.<span><span><span><span>−x </span>− 7</span> + 7</span>=<span> 1+7</span></span><span><span>−x</span>=8</span>
Step 4: Divide both sides by -1.<span><span><span>‌<span><span>−x/</span><span>−1 </span></span></span>‌</span>=<span><span>‌<span> 8/<span>−1</span></span></span>‌</span></span><span>x=<span> −8</span></span>
Answer:<span>x= <span>−<span>8
hope this helps :)</span></span></span>
6 0
3 years ago
A pack of 8 batteries cost 4.72!What is cost per battery?
Mrrafil [7]
4.72 x 1 = 4.72
8 x X =8x
We need to let the X alone so
4.72 divided 8 = 0.59
1 battery = 0.59
8 0
2 years ago
Suppose 2 /7 of students in your school wore shorts today. How many students would you have to select randomly, on average, in o
Sveta_85 [38]

Answer: 49 students

Step-by-step explanation:

2 /7 of students in a school wore shorts today. The number of students to be selected in order to get 14 students who will wear shorts to school will be:

Let the number of students that will be sampled be y. This will be:

2/7 of y = 14

2/7 × y = 14

2y/7 = 14

Cross Multiply

2y = 7 × 14

2y = 98

y = 98/2

y = 49

49 students will be selected randomly.

8 0
3 years ago
Find the limit of the function algebraically. (2 points) limit as x approaches zero of quantity x squared plus two x divided by
DIA [1.3K]

Answer:

DNE

Step-by-step explanation:

\lim_{x \to \0} \frac{x^{2} +2x}{x^{4} }

As you can see in the picture I attached to this, that as the limit goes to zero from the negative side, it approaches -∞ and from the positive side, it approaches ∞ . hence, the limit doesn't exist.

To show this algebraically, you have to imagine how a number divided by zero looks like, Just know the graph of 1/x and see how the limit to zero doesnot exist. I hope this helps!

7 0
3 years ago
Suppose a certain manufacturing company produces connecting rods for 4- and 6-cylinder automobile engines using the same product
gregori [183]

Answer:

Generally the constraint that sets next week are shown below

Generally the constrain that sets next week maximum production of connecting rod for 4 cylinder  to  W_4 or  0 is  

     x_4 \le W_4 *  s_4

    x_4 \le 5000 *  s_4

Generally the constrain that sets next week maximum production of connecting rod for 6 cylinder  to  W_6 or  0  is  

     x_6 \le W_6 *  s_6

     x_6 \le 8,000 *  s_6

Generally the constrain that limits the production of connecting rods  for both 4 cylinder and 6 cylinders  is

     x_4 \le W_4 *  s_6

=>   x_4 \le 5000 *  s_6

     x_4 \le W_6 *  s_4

=>    x_4 \le 8000 *  s_4

     s_4 + s_6 = 1

The minimum cost of production for next week is  

   U  =  M_4 *  x_4 + M_6 * x_6 + C_4 * s_4 + C_6 * s_6

=>  U  =  13x_4 + 16x_6 + 2000 s_4 + 3500 s_6

Step-by-step explanation:

The cost for the four cylinder production line is  C_4 =  \$2,100

The cost for the six cylinder production line is  C_6 = \$3,500

The manufacturing cost for each four cylinder is  M_4= \$13

 The manufacturing cost for each six cylinder is M_6= \$16

  The weekly production capacity for 4 cylinder connecting rod is W_4 = 5,000

   The weekly production capacity for 6 cylinder connecting rod is W_6 = 8,000

Generally the constraint that sets next week are shown below

Generally the constrain that sets next week maximum production of connecting rod for 4 cylinder  to  W_4 or  0 is  

     x_4 \le W_4 *  s_4

    x_4 \le 5000 *  s_4

Generally the constrain that sets next week maximum production of connecting rod for 6 cylinder  to  W_6 or  0  is  

     x_6 \le W_6 *  s_6

     x_6 \le 8,000 *  s_6

Generally the constrain that limits the production of connecting rods  for both 4 cylinder and 6 cylinders  is

     x_4 \le W_4 *  s_6

=>   x_4 \le 5000 *  s_6

     x_4 \le W_6 *  s_4

=>    x_4 \le 8000 *  s_4

     s_4 + s_6 = 1

The minimum cost of production for next week is  

   U  =  M_4 *  x_4 + M_6 * x_6 + C_4 * s_4 + C_6 * s_6

=>  U  =  13x_4 + 16x_6 + 2000 s_4 + 3500 s_6

3 0
3 years ago
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