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Norma-Jean [14]
3 years ago
9

given the f(x)=x2 write the equation function g(x) whose graph is a translation 5 units left and 3 units down

Mathematics
1 answer:
Leno4ka [110]3 years ago
7 0

When a function is translated, it means the function is moved away from its original position.

<em>The function g(x) is: </em>g(x) = (x  + 5)^2 - 3<em />

Give that:

f(x) = x^2

The rule of translation 5 units left is:

(x,y) \to (x + 5, y)

So, we have:

f'(x) = (x + 5)^2

The rule of translation 3 units down is:

(x,y) \to (x, y-5)

So, we have:

g(x) = (x  + 5)^2 - 3

Hence, the function g(x) is: g(x) = (x  + 5)^2 - 3

Read more about translations at:

brainly.com/question/12463306

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Match The exponential expression on the left with the equivalent simplified expression on the right?
Artist 52 [7]

Answer:

Image for the above Question is Missing hence Attached below.

y^{2}y^{4}           ⇒ y^{6}

(2y)^{2}               ⇒ 4y^{2}

(\dfrac{y}{4})^{2}  ⇒\dfrac{y^{2}}{16}

2((y)^{3})^{3}        ⇒ 2y^{9}

Step-by-step explanation:

We have Law of Indices as follow

1.  x^{a}x^{b}=x^{a+b}

2. (xy)^{a}=x^{a}y^{a}

3. (\dfrac{x}{y})^{a}=\dfrac{x^{a}}{y^{a}}

4. ((x)^{a})^{b}=x^{a\times b}

Using above identities we get

For First

y^{2}y^{4}=y^{2+4}=y^{4}

Therefore y^{2}y^{4}   ⇒ y^{6}

For Second

(2y)^{2}=2^{2}y^{2}=4y^{2}

Therefore (2y)^{2}   ⇒ 4y^{2}

For Third

(\dfrac{y}{4})^{2}=\dfrac{y^{2}}{4^{2}}=\dfrac{y^{2}}{16}

Therefore (\dfrac{y}{4})^{2}  ⇒\dfrac{y^{2}}{16}

For Fourth

2((y)^{3})^{3}=2y^{3\times 3}=2y^{9}

Therefore 2((y)^{3})^{3}   ⇒ 2y^{9}

3 0
3 years ago
A: What are the solutions to the quadratic equation?
noname [10]

Answer:

<h2>A. x = -1 or x = 3</h2><h2>B. first</h2>

Step-by-step explanation:

x^2-2x-3=0\\\\x^2+x-3x-3=0\\\\x(x+1)-3(x+1)=0\\\\(x+1)(x-3)=0\iff x+1=0\ \vee\ x-3=0\\\\x+1=0\qquad\text{subtract 1 from both sides}\\x=-1\\\\x-3=0\qquad\text{add 3 to both sides}\\x=3

3 0
3 years ago
10 points plz answer thx
amid [387]

Answer:

(   \sqrt[4]{81} ) {}^{3}

81 {}^{ \frac{1}{4}  \times 3}

81 {}^{( \frac{3}{4}) }

Hope it helps you

3 0
3 years ago
Read 2 more answers
Plz help me out asap
wariber [46]

I think the answer is A.

I haven't learnt this but I think the answer is A.

Reason:

1×8=8

2×8=16

3×8=24

And so.....

7 0
3 years ago
Write the standard form of the equation of the circle with center (7,1) that also contains the point (−1,−5).
Karo-lina-s [1.5K]

Answer:

(x-7)^2+(y-1)^2=100

Step-by-step explanation:

<u>1) Find the radius</u>

We can do this by using the distance equation with the centre (7,1) and the given point (-1,-5):

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} where the two points are (x_1,y_1) and (x_2,y_2)

Plug in the points (7,1) and (-1,-5)

d=\sqrt{(-1-7)^2+(-5-1)^2}\\d=\sqrt{(-8)^2+(-6)^2}\\d=\sqrt{64+36}\\d=\sqrt{100}\\d=10

Therefore, the radius of the circle is 10 units.

<u>2) Plug the data into the equation of a circle</u>

Equation of a circle (when not centred at the origin):

(x-h)^2+(y-k)^2=r^2 where the centre is (h,k) and r is the radius

Plug in the centre (7,1) as (h,k)

(x-7)^2+(y-1)^2=r^2

Plug in the radius 10

(x-7)^2+(y-1)^2=10^2\\(x-7)^2+(y-1)^2=100

I hope this helps!

4 0
3 years ago
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