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Norma-Jean [14]
3 years ago
9

given the f(x)=x2 write the equation function g(x) whose graph is a translation 5 units left and 3 units down

Mathematics
1 answer:
Leno4ka [110]3 years ago
7 0

When a function is translated, it means the function is moved away from its original position.

<em>The function g(x) is: </em>g(x) = (x  + 5)^2 - 3<em />

Give that:

f(x) = x^2

The rule of translation 5 units left is:

(x,y) \to (x + 5, y)

So, we have:

f'(x) = (x + 5)^2

The rule of translation 3 units down is:

(x,y) \to (x, y-5)

So, we have:

g(x) = (x  + 5)^2 - 3

Hence, the function g(x) is: g(x) = (x  + 5)^2 - 3

Read more about translations at:

brainly.com/question/12463306

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Option C is correct

Step-by-step explanation:

      5c – 20 ≤ 15c + 10

<=> 5c - 15c ≤ 20 + 10

<=>-10c ≤ 30

<=> c ≥ -3

Hope this helps!

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snow_lady [41]

Answer:

$2000 was invested at 5% and $5000 was invested at 8%.

Step-by-step explanation:

Assuming the interest is simple interest.

<u>Simple Interest Formula</u>

I = Prt

where:

  • I = interest earned.
  • P = principal invested.
  • r = interest rate (in decimal form).
  • t = time (in years).

Given:

  • Total P = $7000
  • P₁ = principal invested at 5%
  • P₂ = principal invested at 8%
  • Total interest = $500
  • r₁ = 5% = 0.05
  • r₂ = 8% = 0.08
  • t = 1 year

Create two equations from the given information:

\textsf{Equation 1}: \quad \sf P_1+P_2=7000

\textsf{Equation 2}: \quad \sf P_1r_1t+P_2r_2t=I\implies 0.05P_1+0.08P_2=500

Rewrite Equation 1 to make P₁ the subject:

\implies \sf P_1=7000-P_2

Substitute this into Equation 2 and solve for P₂:

\implies \sf 0.05(7000-P_2)+0.08P_2=500

\implies \sf 350-0.05P_2+0.08P_2=500

\implies \sf 0.03P_2=150

\implies \sf P_2=\dfrac{150}{0.03}

\implies \sf P_2=5000

Substitute the found value of P₂ into Equation 1 and solve for P₁:

\implies \sf P_1+5000=7000

\implies \sf P_1=7000-5000

\implies \sf P_1 = 2000

$2000 was invested at 5% and $5000 was invested at 8%.

Learn more about simple interest here:

brainly.com/question/27743947

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