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The value of h(t) when is 10.02.
Solution:
Given function
To find the value of h(t) when :
Substitute in the given function.
Now multiply the common terms into inside the bracket.
Now, in the first term, the numerator and denominator both have common factor 16. So reduce the first term into the lowest term.
To make the denominator same, take LCM of the denominators.
LCM of 64 and 32 = 64
= 10.02
Hence the value of h(t) when is 10.02.
Answer:
Step-by-step explanation:
Given that the height in inches, of a randomly chosen American woman is a normal random variable with mean μ = 64 and variance 2 = 7.84.
X is N(64, 2.8)
Or Z =
a) the probability that the height of a randomly chosen woman is between 59.8 and 68.2 inches.
b)
c) For 4 women to be height 260 inches is equivalent to
4x will be normal with mean (64*4) and std dev (2.8*4)
4x is N(266, 11.2)
d) Z is N(0,1)
E(Z19) =
since normal distribution is maximum only between 3 std deviations form the mean on either side.