Answer:
8 -7/16 y+4/5 p - 3/8 y
-7/16 y -3/8 y expand fraction so it would turn to
-7y/16-3y/8
multiply by 2 on the 3/8 to get a common demominator
-7y/16-6y/16
-7y-6y/16
collect like terms
-13y/16
rewrite fraction
- 13/16y
so the whole equation would turn into
8-13/16y+4/5p
Answer:
B.) The graph of m(x) is wider.
Both graphs open upward.
Both have the axis of symmetry x = 0.
The vertex of m(x) is (0, 4); the vertex of n(x) is (0, 0).
Step-by-step explanation:
When the coefficient before x² is greater than 1, the curve of the graph is narrower. When the coefficient is less than 1, the curve of the graph is wider.
When the coefficient in front of x² is positive, the graph opens upwards. When the coefficient is negative, the graph opens downwards.
The axis of symmetry is the "x" value which divides the curve into two equal sections. Their axis of symmetry are both x = 0 because their vertexes (the lowest point of the curve) are both at x = 0.
The vertex can be found by plugging x = 0 into both of the equations and then solving. The resulting value is the "y" position of the vertex.
m(0) = 0.7(0)² + 4 n(0) = (0)²
m(0) = 0 + 4 n(0) = 0
m(0) = 4
Therefore, the vertexes are m(x) = (0,4) and n(x) = (0,0).
Multiplication property of association
Answer:
B
Step-by-step explanation:
Okay, so this is a fairly challenging problem.
Parallel lines have the same slop, but different y-intercepts.
The new equation is y = 4/3 x + b
Now substitute x and y for the point's coordinates...
-4 = 4/3 (3) + b
(solve for b)
-4 = 12/3 + b
-4 = 4 + b
b = -8
The final equation is:
y = 4/3 x - 8
In point-slope form, this is B
