Answer:
Minimum coefficient of kinetic friction between the surface and the block is
.
Explanation:
Given:
Mass of the block = M
Spring constant = k
Distance pulled = x
According to the question:
<em>We have to find the minimum co-efficient of kinetic friction between the surface and the block that will prevent the block from returning to its equilibrium with non-zero speed. </em>
So,
From the FBD we can say that:
⇒ Normal force,
<em>...equation(i)</em>
⇒ Elastic potential energy,
=
<em> ...equation (ii)</em>
⇒ Frictional force,
=
<em> ...equation (iii)</em>
⇒ Plugging (i) in (iii).
⇒
Now,
⇒ As we know that the energy lost due to friction is equivalent to PE .
⇒
<em>...considering PE as</em>
or
.
Arranging the equation.
⇒ 
⇒
<em>...eliminating x from both sides.</em>
⇒
<em>...dividing both sides wit Mg.</em>
Minimum coefficient of kinetic friction between the surface and the block is
.
The ball with greater mass has more density
Answer:
Velocity of truck will be 20.287 m /sec
Explanation:
We have given mass of the truck m = 4000 kg
Radius of the turn r = 70 m
Coefficient of friction 
Centripetal force is given 
And frictional force is equal to 
For body to be move these two forces must be equal
So 
