Answer:
68?
Step-by-step explanation:
multiples of 5 end in 5 or 0
_ _ _
last digit has 2 choices ( 5 and 0 )
1,3,5,7,9 are odd
so tens digit has 5 choices but we see that 5 is repeated so we split into more cases
when last digit is 0, tens digit has 5 choices then hundreds digit has 8 choices so 1*5*8=40
when last digit is 5, tens digit has 4 choices and hundreds digit has 7 choices (0 can't be first digit) 1*4*7=28
40+28=68
Answer: SOLUTION: find three cosecutive odd integers such that the sum of the least and greatest is 78. Let x, x+2, x+4 b the 3 consecutive odd integers. 37, 39, 41.
Step-by-step explanation: look above lol hope this helps u gud luk
Answer: 
= -33
Step-by-step explanation:
-6, -9, -12, -15
The common difference is -3
d = common difference
Arithmetic sequence formula:
= 
+ (n - 1) d
= -6 + (10 - 1) -3
= -6 + 9 × -3
= -6 - 27
= -33
So to find x, you have to add both A and B which is 38. Since AuB (excluding the overlap) is 29, subtract 38 from 29 and you get 9 for x.
Let the number of yards she trimmed be t
She trimmed 5 more yards than she cut and she mad $415, so
20t+15(t-5)=415
We first distribute the second number so this equals
20t+15t-75=415
Then we add 75 to both sides, getting
20t+15t=490
This means that
35t=490
And we divide both sides by 35 to get
t=14
So, she trimmed 14 yards
