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Monica [59]
4 years ago
12

Please help it's due tomorrow

Mathematics
2 answers:
kondaur [170]4 years ago
6 0
7 in 4 rows sry for copying i am trying 2 rank 
telo118 [61]4 years ago
5 0
There would be 7 in 4 rows
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Anna has a right triangle with side lengths 13,4 and 12. She believes that the right triangle with a side length of 12 is the hy
Vikentia [17]
Yes I believe Anna is correct, but I feel this question needs more context, hope t helps :)
8 0
3 years ago
Jk/j+k when j = 6 and k = 12
arlik [135]

Answer: I'm pretty sure it's 15

Step-by-step explanation:

18/6+12

3+12

15

3 0
3 years ago
❤❤❤❤❤❤❤help please ❤❤❤❤❤❤❤❤❤❤❤
irina [24]
Forms for the equation of a straight line

Suppose that we have the graph of a straight line and that we wish to find its equation. (We will assume that the graph has x and y axes and a linear scale.) The equation can be expressed in several possible forms. To find the equation of the straight line in any form we must be given either:
two points, (x1, y1) and (x2, y2), on the line; or
one point, (x1, y1), on the line and the slope, m; or
the y intercept, b, and the slope, m.
In the first case where we are given two points, we can find m by using the formula:

Once we have one form we can easily get any of the other forms from it using simple algebraic manipulations. Here are the forms:


1. The slope-intercept form:
y = m x + b.
The constant b is simply the y intercept of the line, found by inspection. The constant m is the slope, found by picking any two points (x1, y1) and (x2, y2) on the line and using the formula:



2. The point-slope form:
y − y1 = m (x − x1).
(x1, y1) is a point on the line. The slope m can be found from a second point, (x2, y2), and using the formula:



3. The general form:
a x + b y + c = 0.
a, b and c are constants. This form is usually gotten by manipulating one of the previous two forms. Note that any one of the constants can be made equal to 1 by dividing the equation through by that constant.



4. The parametric form:
7 0
4 years ago
An arborist wants to prune an oak tree that has grown too tall. The arborist takes a 15-foot ladder and places it on a horizonta
SCORPION-xisa [38]
See the attached picture to better understand the problem

we know that
in the right triangle ABC
cos 70=adjacent side angle 70/hypotenuse
adjacent side angle 70=BC----> <span>distance between the ladder and the tree trunk
hypotenuse=AC------> 15 ft

cos 70=BC/AC-------> solve for BC
BC=AC*cos 70------> BC=15*cos 70-----> BC=5.13 ft

the answer is
the </span>distance between the ladder and the tree  is 5.13 ft<span>

</span>

8 0
3 years ago
Evaluate -4/(4)2??????????!!!!!!!!!!
scoray [572]

Answer:

-4/2 is equal to -2.

-2 times -4 is equal to 8.

Therefore, (-4)-4/2

5 0
4 years ago
Read 2 more answers
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