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serious [3.7K]
3 years ago
14

a dog weighs two pounds less than three times the weight of a cat. The dog also weighs twenty-two more pounds than the cat. writ

e and solve an equation to find the weights of the dog and the cat.
Mathematics
1 answer:
Law Incorporation [45]3 years ago
8 0

Answer:

Weight of dog: 34 pounds,

Weight of cat: 12 pounds.

Step-by-step explanation:

Let d represent weight of dog and c represent weight of cat.

We have been given that a dog weighs two pounds less than three times the weight of a cat.

3 times weight of cat: 3c

We can represent the given information in an equation as: d=3c -2...1

We are also told that the dog also weights twenty-two more pounds than the cat. We can represent the given information in an equation as:

d=c+22...(2)

3c-2=c+22--->c=12

Therefore subsitute c=12 in equation 2

d=+22

d=12+22

d=34

Therefore, the weight of dog is 34 pounds.

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I hope this helped!
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3 years ago
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Dmitriy789 [7]

Answer:

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Step-by-step explanation:

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2 years ago
Let A and B be sets with cardinal numbers , n(A) = a and n(B) = b respectively . Decide whether the statement is true or false.
olya-2409 [2.1K]

Answer:

True

Step-by-step explanation:

A\cup B=A\cup(A-B)\\\\A\ and\ A-B\ are\ disjoint\ that\ means\ there\ is\ no\ common\ element\ in\ these\ two.\\\\n(A\cup B)=n(B\cup(A-B))\\\\n(A\cup B)=n(B)+n(A-B)\ \ \ \ \ \ \ as\ for\ disjoint\ set\ P,Q\ n(P\cup Q)=n(P)+n(Q)\\\\(n(P-Q)=n(P)-n(P\cap Q))\\\\n(AUB)=n(B)+n(A-B)\\\\n(AUB)=n(B)+n(A)-n(A\cap B)\\\\n(AUB)=n(A)+n(B)-n(A\cap B)\\\\Hence\ given\ statement\ is\ true

4 0
3 years ago
A watermelon seed is 0.4cm long. How far would a line of 124 watermelon seeds stretch? Write your answer in meters.
Ahat [919]
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Answer is 0.496 meters
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3 years ago
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