The point P is on the unit circle. Find P(x, y) from the given information.

1 answer:

5 0

I always understood the unit circle to have a radius of 1 and be centered on the origin (0,0). That there are two x coordinates confuses me. Neither 8 nor 17 is an x value for a line passing through the unit circle, so I'm going to guess "8/17" is the actual x coordinate (which is between -1 and 1). P(8/17,y) = x^2 + y^2 = 1.

289/289 - 64/289 = 225/289. The square root of that (positive since y is positive) yields 15/17. P(x,y) = 8/17, 15/17.

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