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monitta
3 years ago
8

The point P is on the unit circle. Find P(x, y) from the given information.

Mathematics
1 answer:
bekas [8.4K]3 years ago
5 0
I always understood the unit circle to have a radius of 1 and be centered on the origin (0,0).  That there are two x coordinates confuses me.  Neither 8 nor 17 is an x value for a line passing through the unit circle, so I'm going to guess "8/17" is the actual x coordinate (which is between -1 and 1).  P(8/17,y) = x^2 + y^2 = 1.

289/289 - 64/289 = 225/289.  The square root of that (positive since y is positive) yields 15/17.  P(x,y) = 8/17, 15/17.
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svetlana [45]
-4\frac{7}{8}=-4\frac{7\cdot125}{8\cdot125}=-4\frac{875}{1000}=\boxed{-4.875}
4 0
2 years ago
What is csc ( Reduce fractional answers to lowest terms.
harina [27]

Answer:

cscA = \frac{5}{4}

Step-by-step explanation:

Using the identity

csc x = \frac{1}{sinx} , then

sinA = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{8}{10} = \frac{4}{5} , thus

cscA = \frac{1}{\frac{4}{5} } = \frac{5}{4}

4 0
2 years ago
PLEASE SHOW ALL THE STEPS THAT YOU USE TO SOLVE THIS PROBLEM
Mademuasel [1]

Answer:

{x = 1 , y=1, z=0

Step-by-step explanation:

Solve the following system:

{-2 x + 2 y + 3 z = 0 | (equation 1)

{-2 x - y + z = -3 | (equation 2)

{2 x + 3 y + 3 z = 5 | (equation 3)

Subtract equation 1 from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x - 3 y - 2 z = -3 | (equation 2)

{2 x + 3 y + 3 z = 5 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+3 y + 2 z = 3 | (equation 2)

{2 x + 3 y + 3 z = 5 | (equation 3)

Add equation 1 to equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+3 y + 2 z = 3 | (equation 2)

{0 x+5 y + 6 z = 5 | (equation 3)

Swap equation 2 with equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y + 6 z = 5 | (equation 2)

{0 x+3 y + 2 z = 3 | (equation 3)

Subtract 3/5 × (equation 2) from equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y + 6 z = 5 | (equation 2)

{0 x+0 y - (8 z)/5 = 0 | (equation 3)

Multiply equation 3 by 5/8:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y + 6 z = 5 | (equation 2)

{0 x+0 y - z = 0 | (equation 3)

Multiply equation 3 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y + 6 z = 5 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Subtract 6 × (equation 3) from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y+0 z = 5 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Divide equation 2 by 5:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+y+0 z = 1 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Subtract 2 × (equation 2) from equation 1:

{-(2 x) + 0 y+3 z = -2 | (equation 1)

{0 x+y+0 z = 1 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Subtract 3 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = -2 | (equation 1)

{0 x+y+0 z = 1 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = 1 | (equation 1)

{0 x+y+0 z = 1 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Collect results:

Answer:  {x = 1 , y=1, z=0

6 0
2 years ago
Point M is on line segment \overline{LN} LN . Given LN=17LN=17 and MN=3,MN=3, determine the length \overline{LM}. LM .
Alinara [238K]

Answer:

14

Step-by-step explanation:

the full length of the line is 17, half of it is 3.

subtract line LN from MN to get LM.

17-3=14

8 0
2 years ago
To bill customers for water usage, one city converts the number of gallons used into units. This relationship is represented by
Anastaziya [24]

We are given equation g = 748u, where g is the total number of gallons of water used and u is the number of units.

We can see that the number of units of water being used by customers.

The number of units of water doesn't depend on the total number of gallons of water used.  

Therefore, the number of units u is an independent variable.

The value of the total number of gallons is totally depends on the number of units used.

Therefore,  the total number of gallons of water used g is a dependent variable.

So, we can conclude following statements:

1) g is the dependent variable.

2) u is the independent variable.

6 0
2 years ago
Read 2 more answers
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