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3 years ago

8

The point P is on the unit circle. Find P(x, y) from the given information.

1 answer:

bekas [8.4K]3 years ago

5 0

I always understood the unit circle to have a radius of 1 and be centered on the origin (0,0). That there are two x coordinates confuses me. Neither 8 nor 17 is an x value for a line passing through the unit circle, so I'm going to guess "8/17" is the actual x coordinate (which is between -1 and 1). P(8/17,y) = x^2 + y^2 = 1.

289/289 - 64/289 = 225/289. The square root of that (positive since y is positive) yields 15/17. P(x,y) = 8/17, 15/17.

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Find The Midpoint of the coordinate system P( -4 , 4 ) and (4,8)

Stella [2.4K]

Answer:

Step-by-step explanation:

(-4+4)/2 = 0/2 = 0

(4+8)/2 =12/2= 6

(0, 6)

3 0

3 years ago

If each unit cube has edges 3/4 foot long, what is the volume of the blue-outlined prism?

denpristay [2]

Has someone answered this I need the answer...do u know it??

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Solve this with me plz plz plz plz

Ulleksa [173]

Answer:

5b+1c=3b+5c

Step-by-step explanation:

Let's use the variable c for the circles and b for the boxes.

The weights are the same on both sides, so count the boxes and circles on each side.

There are 5 boxes and 1 circle on the left side. The left side of the equation says 5b+1c.

There are 3 boxes and 5 circles on the right side. The right side of the equation says 3b+5c.

And since the 2 sides are equal, you split the 2 sides of the equation with =.

5b+1c=3b+5c

8 0

3 years ago

If W(-10, 4), X(-3, -1), and Y(-5, 11) classify ΔWXY by its sides. Show all work to justify your answer.

solniwko [45]

Given:

The vertices of ΔWXY are W(-10, 4), X(-3, -1), and Y(-5, 11).

To find:

Which type of triangle is ΔWXY by its sides.

Solution:

Distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using distance formula, we get

$WX=\sqrt{(-3-(-10))^2+(-1-4)^2}$

$WX=\sqrt{(-3+10)^2+(-5)^2}$

$WX=\sqrt{(7)^2+(-5)^2}$

$WX=\sqrt49+25}$

$WX=\sqrt{74}$

Similarly,

$XY=\sqrt{\left(-5-\left(-3\right)\right)^2+\left(11-\left(-1\right)\right)^2}=2\sqrt{37}$

$WY=\sqrt{\left(-5-\left(-10\right)\right)^2+\left(11-4\right)^2}=\sqrt{74}$

Now,

$WX=WY$

So, triangle is an isosceles triangles.

and,

$WX^2+WY^2=(\sqrt{74})^2+(\sqrt{74})^2$

$WX^2+WY^2=74+74$

$WX^2+WY^2=148$

$WX^2+WY^2=(2\sqrt{37})^2$

$WX^2+WY^2=WY^2$

So, triangle is right angled triangle.

Therefore, the ΔWXY is an isosceles right angle triangle.

3 0

3 years ago

The area of room in a dollhouse is 1248 sq in. the width of the room is 8 in. how long is the room?

Tanzania [10]

The length of the room is 156 sq in

6 0

3 years ago