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2 years ago

Need answer ASAP! 1 + 1 =

Mathematics

2 answers:

Svet_ta [14]2 years ago

7 0

Answer:

1+1 =2 man this is the most complicated math i have ever done XD

Step-by-step explanation:

OlgaM077 [116]2 years ago

4 0

Answer:

Step-by-step explanation:

I hope this helps!

You might be interested in

What is 8 3/5 + 4 4/5?

dangina [55]

Answer:

67/5 = 13 2/5

Step-by-step explanation:

Step 1: Define/explain.

An easier way to solve this is by changing the mixed fractions to improper fractions.

To do this, multiply the whole number by the denominator, then add the product to the numerator; the denominator remains the same.

Mixed fraction - a fraction with a whole number.

Improper fraction - a fraction with a numerator larger than the denominator.

Step 2: Solve.

$8\frac{3}{5} =\frac{43}{5}$

$4\frac{4}{5} =\frac{24}{5}$

From here, add as usual.

$\frac{43}{5} +\frac{24}{5} =\frac{67}{5}$

Step 3: Conclude.

You can change the improper fraction to a mixed fraction if you'd like.

To do this, divide the numerator by the denominator.

The amount of times the numerator evenly goes into the denominator is the whole number.

The amount of remaining numbers in the denominator.

The numerator remains the same.

$\frac{67}{5} =13\frac{2}{5}$

I, therefore, believe the answer to this is 13 2/5.

5 0

2 years ago

I hate copy and pastes

tangare [24]

Answer:

why they're so helpful

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

I have underlined the volume of water needed (left) and the volume of chemicals needed (right). How much of the chemical would I

makkiz [27]

3.2 I do believe....

8 0

2 years ago

Help me please I'm bad at geometry

iren [92.7K]

It’s actually all except bottom left

3 0

3 years ago

Evaluate the integral by changing to polar coordinatesye^x dA, where R is in the first quadrant enclosed by the circle x^2+y^2=2

34kurt

$\displaystyle\iint_Rye^x\,\mathrm dA=\int_{\theta=0}^{\theta=\pi/2}\int_{r=0}^{r=5}r^2\sin\theta e^{r\cos\theta}\,\mathrm dr\,\mathrm d\theta$

which follows from the usual change of coordinates via

$\begin{cases}\mathbf x(r,\theta)=r\cos\theta\\\mathbf y(r,\theta)=r\sin\theta\end{cases}$

and Jacobian determinant

$|\det J|=\left|\begin{vmatrix}\mathbf x_r&\mathbf x_\theta\\\mathbf y_r&\mathbf y_\theta\end{vmatrix}\right|=|r|$

Swap the order, so that the integral is

$\displaystyle\int_{r=0}^{r=5}\int_{\theta=0}^{\theta=\pi/2}r^2\sin\theta e^{r\cos\theta}\,\mathrm d\theta\,\mathrm dr$

and now let $\sigma=r\cos\theta$ , so that $\mathrm d\sigma=-r\sin\theta$ . Now, you have

$\displaystyle\int_{r=0}^{r=5}\int_{\sigma=0}^{\sigma=r}re^\sigma\,\mathrm d\sigma\,\mathrm dr=\int_{r=0}^{r=5}r(e^r-1)\,\mathrm dr=4e^5-\dfrac{23}2$

7 0

3 years ago