Carbon can form four covalent bonds. Covalent bonds are chemical bonds that form between nonmetals. In a covalent bond, two atoms share a pair of electrons. By forming four covalent bonds, carbon shares four pairs of electrons, thus filling its outer energy level and achieving stability.
2-7 days, but depends on the procedure
The force of gravity on the 1 kg box is 2 N.
The formula for the force of gravity <em>F</em> on an object with mass <em>m</em> is
<em>F</em> = (<em>GmM</em>)/<em>d</em>²
Since <em>G</em>, <em>M</em> , and <em>d</em> are the same for both objects, (<em>GM</em>)/<em>d</em>² = a constant = <em>k
</em>). Then, we can write
<em>F = km
</em>
<em>F</em>₂/<em>F</em>₁ = <em>m</em>₂/<em>m</em>₁
<em>F</em>₂ = <em>F</em>₁ × <em>m</em>₂/<em>m</em>₁
If the 2.5 kg box is object 1,
<em>F</em>₂= 6.1 N × (1 kg/2.5 kg) = 2 N
<em>Note</em>: The answer can have <em>only one significant figure</em> because that is all you gave for the mass of the 1 kg object.
Answer:
65.08 g.
Explanation:
- For the reaction, the balanced equation is:
<em>2AlCl₃ + 3Br₂ → 2AlBr₃ + 3Cl₂,</em>
2.0 mole of AlCl₃ reacts with 3.0 mole of Br₂ to produce 2.0 mole of AlBr₃ and 3.0 mole of Cl₂.
- Firstly, we need to calculate the no. of moles of 36.2 grams of AlCl₃:
<em>n = mass/molar mass</em> = (36.2 g)/(133.34 g/mol) = <em>0.2715 mol.</em>
<u><em>Using cross multiplication:</em></u>
2.0 mole of AlCl₃ reacts with → 3.0 mole of Br₂, from the stichiometry.
0.2715 mol of AlCl₃ reacts with → ??? mole of Br₂.
∴ The no. of moles of Br₂ reacts completely with 0.2715 mol (36.2 g) of AlCl₃ = (0.2715 mol)(3.0 mole)/(2.0 mole) = 0.4072 mol.
<em>∴ The mass of Br₂ reacts completely with 0.2715 mol (36.2 g) of AlCl₃ = no. of moles of Br₂ x molar mass</em> = (0.4072 mol)(159.808 g/mol
) = <em>65.08 g.</em>
The answer is 0.05706 mols. I included how I got this in the photo below. Hope this helps!
