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AfilCa [17]
3 years ago
11

Differences in the moons and suns pull on different sides of earth cause _______

Chemistry
1 answer:
Aleksandr [31]3 years ago
5 0

Answer:

tides are caused mainly by the differences in how much gravity from the moon and the sun pulls on different parts of earth

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Which term best indicates the average mass of an atom of an element?
Firdavs [7]
The answer is the atomic mass.
8 0
4 years ago
Read 2 more answers
Where does a mid ocean ridge form?
Anit [1.1K]
<span>There are divergent boundaries where the plates are moving away from each other, causing magma to rise up. The boiling lava is almost immediately cooled and forms new sea floor crust.</span>
8 0
4 years ago
From the value Kf=1.2×109 for Ni(NH3)62+, calculate the concentration of NH3 required to just dissolve 0.016 mol of NiC2O4 (Ksp
Nina [5.8K]

<u>Answer:</u> The concentration of NH_3 required will be 0.285 M.

<u>Explanation:</u>

To calculate the molarity of NiC_2O_4, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Moles of NiC_2O_4 = 0.016 moles

Volume of solution = 1 L

Putting values in above equation, we get:

\text{Molarity of }NiC_2O_4=\frac{0.016mol}{1L}=0.016M

For the given chemical equations:

NiC_2O_4(s)\rightleftharpoons Ni^{2+}(aq.)+C_2O_4^{2-}(aq.);K_{sp}=4.0\times 10^{-10}

Ni^{2+}(aq.)+6NH_3(aq.)\rightleftharpoons [Ni(NH_3)_6]^{2+}+C_2O_4^{2-}(aq.);K_f=1.2\times 10^9

Net equation: NiC_2O_4(s)+6NH_3(aq.)\rightleftharpoons [Ni(NH_3)_6]^{2+}+C_2O_4^{2-}(aq.);K=?

To calculate the equilibrium constant, K for above equation, we get:

K=K_{sp}\times K_f\\K=(4.0\times 10^{-10})\times (1.2\times 10^9)=0.48

The expression for equilibrium constant of above equation is:

K=\frac{[C_2O_4^{2-}][[Ni(NH_3)_6]^{2+}]}{[NiC_2O_4][NH_3]^6}

As, NiC_2O_4 is a solid, so its activity is taken as 1 and so for C_2O_4^{2-}

We are given:

[[Ni(NH_3)_6]^{2+}]=0.016M

Putting values in above equations, we get:

0.48=\frac{0.016}{[NH_3]^6}}

[NH_3]=0.285M

Hence, the concentration of NH_3 required will be 0.285 M.

7 0
3 years ago
For a certain experiment, a student requires 100 milliliters of a solution that is 8% HCl (hydrochloric acid). The storeroom has
exis [7]

Answer:

70 mL of 5% HCl and 30 mL of 15% HCl

Explanation:

We will designate x to be the fraction of the final solution that is composed of 5% HCl, and y to be the fraction of the final solution that is composed of 15% HCl. Since the percentage of the final solution is 8%, we can write the following expression:

5x + 15y = 8

Since x and y are fractions of a total, they must equal one:

x + y = 1

This is a system of two equations with two unknowns. We will proceed to solve for x. First, an expression for y is found:

y = 1 - x

This expression is substituted into the first equation and we solve for x.

5x + 15(1 - x) = 8

5x+ 15 - 15x = 8

-10x = -7

x = 7/10 = 0.7

We then calculate the value of y:

y = 1 - x = 1 - 0.7 = 0.3

Thus 0.7 of the 100 mL will be the 5% HCl solution, so the volume of 5% HCl we need is:

(100 mL)(0.7) = 70 mL

Similarly, the volume of 15% HCl we need is:

(100 mL)(0.3) = 30 mL

3 0
4 years ago
The volume of a Goodyear Blimp is 2.5x10^7 L, which is occupied by 1.7x10^6 mol of helium. What is the internal pressure of the
attashe74 [19]

Answer:

1.7 bar

Explanation:

We can use the <em>Ideal Gas Law</em> to calculate the individual gas pressure.

pV = nRT     Divide both sides by V

 p = (nRT)/V

Data:   n = 1.7 × 10⁶ mol

R = 0.083 14 bar·L·K⁻¹mol⁻¹

T = 22 °C

V = 2.5 × 10⁷ L

Calculations:

(a) <em>Change the temperature to kelvins </em>

T = (22 + 273.15) K

  = 295.15 K

(b) Calculate the pressure

p = (1.7 × 10⁶ × 0.083 14 × 295.15)/(2.5× 10⁷)

  = 1.7 bar

4 0
3 years ago
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