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adelina 88 [10]
3 years ago
13

Help please i’ll give extra points

Chemistry
1 answer:
joja [24]3 years ago
7 0

Answer:

okay no problem

I will give

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Given the following unbalanced equation:
LUCKY_DIMON [66]
52.28 if I’m not wrong!
5 0
3 years ago
Calculate the Ka for the following acid. Determine if it is a strong or weak acid. HClO2(aq) dissolves in aqueous solution to fo
Talja [164]

Answer:

The value of Ka = 1.1*10^{-2}

It is a weak  acid

Explanation:

   From the question we are told that

             The concentration of [HClO_2]=0.24M

             The concentration of  [H^+]=0.051M

             The concentration of  [ClO_2^-]=0.051M

Generally the equation for the ionic dissociation of HClO_2 is

                HClO_2_(aq) -------> H^{+}_{(aq)} + ClO_2^{-}_{(aq)}

The equilibrium constant is mathematically represented as

                         Ka = \frac{concentration  \ of  \ product  }{concentration \ of \  reactant }

                               = \frac{[H^+][ClO_2^-]}{[HClO_2]}

Substituting values since all value of concentration are at equilibrium

                    Ka = \frac{0.051 * 0.051}{0.24}

                          = 1.1*10^{-2}

Since the value of  is less than 1 it show that in water it dose not completely

disassociated  so it an acid that is weak

                         

               

3 0
3 years ago
A compound contains only carbon, hydrogen, nitrogen, and oxygen. Combustion of 0.157g of the compound produced 0.213g of CO2 and
vladimir2022 [97]

Answer:

C_{7} H_{5}N_{3}O_{6}

Explanation:

First reaction gives you the number of moles or the mass from Carbon and hydrogen

for carbon:

0,213gCO_{2} .\frac{1molCO_{2}}{44gCO_{2}} .\frac{1molC}{1molCO_{2}} =0.005molC

0.213gCO_{2} .\frac{1molCO_{2}}{44gCO_{2}} .\frac{1molC}{1molCO_{2}} .\frac{12gC}{1molC} = 0.058gC\\

Analogously for hydrogen:

0.0310gH_{2}O have 0.0034gH or 0.0034mol of H

In the second reaction you can obtain the amount of nitrogen as a percentage and find the mass of N in the first sample.

0.023gNH_{3} .\frac{1molNH_{3}}{17gNH_{3}} .\frac{1molN}{1molNH_{3}} .\frac{14gN}{1molN} \frac{100}{0.103gsample} =18.4%N

now

\frac{18.4gN}{100gsample} .0.157gsample=0.0289gN in the first reaction

this is equivalet to 0.002mol of N

with this information you can find the mass of oxygen by matter conservation.

gO=total mass-(gN+gC+gH)=0.157-(0.0289+0.058+0.0034)=0.0666gO

this is equivalent to 0.004molO

finally you divide all moles obtained between the smaller number of mole (this is mol of H)

C\frac{0.0048}{0.0034} H\frac{0.0034}{0.0034} N\frac{0.002}{0.0034} O\frac{0.004}{0.0034} =C_{1.4} HN_{0.6} O_{1.2}

and you can multiply by  5   to obtain: C_{7} H_{5}N_{3}O_{6}

4 0
3 years ago
Lionel places red blood cells in a beaker of pure water, and then he observes their
scZoUnD [109]

Answer:

The red blood cells will burst

Explanation:

When the red blood cells are placed in pure water, they will gain water by osmosis, swell and finally burst due to their weak cell membranes. This process is referred to as hemolysis.

7 0
3 years ago
In a nuclear reaction, which of the following must be conserved?
dolphi86 [110]

Answer:

A. Energy  must be conserved in a nuclear reaction

Explanation:

8 0
3 years ago
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