If It takes 60mL of 0.20M of sodium hydroxide (NaOH) to neutralize 25 mL of carbonic acid (
), then the concentration of the carbonic acid is 0.24M
The reaction between NaOH solution and
is written below
![2NaOH + H_2CO_3 \rightarrow Na_2CO_3 + 2H_2O](https://tex.z-dn.net/?f=2NaOH%20%2B%20H_2CO_3%20%5Crightarrow%20Na_2CO_3%20%2B%202H_2O)
Volume of NaOH,
= 60 ml
Volume of
, ![V_A=25 ml](https://tex.z-dn.net/?f=V_A%3D25%20ml)
Molarity of
, ![C_A=?](https://tex.z-dn.net/?f=C_A%3D%3F)
Molarity of NaOH, ![C_B=0.20M](https://tex.z-dn.net/?f=C_B%3D0.20M)
Number of moles of
, ![n_A=1](https://tex.z-dn.net/?f=n_A%3D1)
Number of moles of NaOH, ![n_B=2](https://tex.z-dn.net/?f=n_B%3D2)
The mathematical equation for neutralization reaction is:
![\frac{C_AV_A}{C_BV_B} =\frac{n_A}{n_B}](https://tex.z-dn.net/?f=%5Cfrac%7BC_AV_A%7D%7BC_BV_B%7D%20%3D%5Cfrac%7Bn_A%7D%7Bn_B%7D)
Substitute
,
,
,
= 60ml, and
into the equation above in order to solve for ![C_A](https://tex.z-dn.net/?f=C_A)
![\frac{C_A \times 25}{0.2 \times 60}=\frac{1}{2} \\\\50C_A=12\\\\C_B=\frac{12}{50} \\\\C_B=0.24M](https://tex.z-dn.net/?f=%5Cfrac%7BC_A%20%5Ctimes%2025%7D%7B0.2%20%5Ctimes%2060%7D%3D%5Cfrac%7B1%7D%7B2%7D%20%20%5C%5C%5C%5C50C_A%3D12%5C%5C%5C%5CC_B%3D%5Cfrac%7B12%7D%7B50%7D%20%5C%5C%5C%5CC_B%3D0.24M)
Therefore, the concentration of the carbonic acid is 0.24M
Learn more here: brainly.com/question/25943090
Fishes yes according to the age, reptiles yes
It’s the second answer. “it gets used for metabolic process & released as heat” i think.
Add 7 water atom to the right hand side to adjust the quantity of oxygen. Increase Cr(+3) by two to adjust the quantity of Cr. Duplicate Cl-by two to adjust the quantity of chlorine molecules.
Cr2O7[2-](aq) +2 Cl[-](aq) < - >2 Cr[3+] (aq) + Cl2(g)+7H2O
Presently adjust that charges.
you have - 4 charges on the left hand side, while +18 charges on the right hand side, there for include 14H+ the left hand side to adjust the charges
Cr2O7[2-](aq) +2 Cl[-](aq)+14H+ < - >2 Cr[3+] (aq) + Cl2(g)+7H2O
take note of that the oxidation number of hydrogen in water is +1