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3 years ago

Is the following relation a function yes or no (9th-grade algebra 1)

Mathematics

2 answers:

solniwko [45]3 years ago

5 0

Answer: its yes

Step-by-step explanation:

Alexxx [7]3 years ago

4 0

The given relation is NOT a function. By definition, a function is a relation in which no two ordered pairs have the same first component and different second components. In your given table, the y = -2 has two corresponding x values: it is paired with x = -1 and x = 6. Therefore, it is not a function.

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Solve each question for the variable.

ivolga24 [154]

Answer:

530.087 trust me

Step-by-step explanation:

8 0

3 years ago

Need help please help me

ANTONII [103]

Megan:
x to the one third power = $x ^{1/3}$
x to the one twelfth power = $x ^{1/12}$

The quantity of x to the one third power, over x to the one twelfth power is:
 $\frac{x ^{1/3}}{x ^{1/12}}$

Since $\frac{ x^{a} }{ x^{b} } = x ^{a-b}$
then $\frac{x ^{1/3}}{x ^{1/12}} = x^{1/3-1/12}$

Now, just subtract exponents:
1/3 - 1/12 = 4/12 - 1/12 = 3/12 = 1/4

$\frac{x ^{1/3}}{x ^{1/12}} = x^{1/3-1/12} = x^{1/4}$

Julie:
x times x to the second times x to the fifth = x * x² * x⁵

The thirty second root of the quantity of x times x to the second times x to the fifth is
 $\sqrt[32]{x* x^{2} * x^{5} }$

Since $x^{a}* x^{b}= x^{a+b}$
Then $\sqrt[32]{x* x^{2} * x^{5} }= \sqrt[32]{ x^{1+2+5} } =\sqrt[32]{ x^{8} }$

Since $\sqrt[n]{x^{m}} = x^{m/n} }$
Then $\sqrt[32]{ x^{8} }= x^{8/32} = x^{1/4}$

Since both Megan and Julie got the same result, it can be concluded that their expressions are equivalent.

3 0

3 years ago

What are the dimensions of the product?

Oksi-84 [34.3K]

Answer:

Step-by-step explanation:

Dimensions: m x n

m = number of rows

n = number of columns

When multiplying two matrices:

m x n * n x k = m x k

MATIX 1:

m = number of rows

n = number of columns

MATRIX 2:

n = number of rows

k = number of columns

RESULTING MATIX:

m = number of rows

k = number of columns

2 x 3 * 3 x 2 = 2 x 2

8 0

3 years ago

Read 2 more answers

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

lilavasa [31]

Answer:

(5a−3)^2

Step-by-step explanation:

25a^2 - 30a + 9

Factor the expression by grouping. First, the expression needs to be rewritten as 25a^2+pa+qa+9. To find p and q, set up a system to be solved.

p+q=−30

pq=25×9=225

Since pq is positive, p and q have the same sign. Since p+q is negative, p and q are both negative. List all such integer pairs that give product 225.

−1,−225

−3,−75

−5,−45

−9,−25

−15,−15

Calculate the sum for each pair.

−1−225=−226

−3−75=−78

−5−45=−50

−9−25=−34

−15−15=−30

The solution is the pair that gives sum −30.

p=−15

q=−15

Rewrite 25a^2 - 30a + 9 as (25a^2−15a)+(−15a+9).

(25a^2−15a)+(−15a+9)

Factor out 5a in the first and −3 in the second group.

5a(5a−3)−3(5a−3)

Factor out common term 5a−3 by using distributive property.

(5a−3)(5a−3)

Rewrite as a binomial square.

(5a−3)^2

3 0

3 years ago

15 POINTS

RoseWind [281]

Answer:

that will be .... x=2,y=1 so that will be (2,1)

3 0

3 years ago