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4 years ago

Examine the first two steps used to solve the equation.

Mathematics

2 answers:

Ksju [112]4 years ago

6 0

Answer:

C. Subtract 11/2y from each side of the equation.

Step-by-step explanation:

bija089 [108]4 years ago

5 0

Answer:

Step-by-step explanation:

Your fractions are missing there fraction bars:

3/4 (20y − 8) + 5 = 1/2 y + 1/4 (20y + 8)

15y − 6 + 5 = 1/2 y + 5y + 2

15y − 1 = 11/2 y + 2

A. 11/2y and 2 aren't like terms because one contains the variable y and the other contains no variable

B. The distribute property can't be used there because you don't have 15(y-1) you have 15y-1

C. Subtracting 11/2y sounds like a good step because there is a y term on the opposing side.

15y-1=11/2y+2

Subtracing 11/2y on both sides

9.5y-1=2

That looks pretty good because then you would add 1 on both sides giving:

9.5y =3

Last step would get the y by itself which is dividing both sides by 9.5 giving you 6/19.

D. You could actually do this but it doesn't help you get x by itself. The equation would look like this: 15/2 y-1/2=11/4 y+1

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15 is at least the quotient of a number and 6 increased by 3

crimeas [40]

Answer:

The number is $x\geq 72$

Step-by-step explanation:

Given:

Quotient $\geq$ 15

Let the number be $x$

The quotient is 15 of a number and 6 which is increaase by 3

Hence forming the inequality expression from the question given we get;

$\frac{x}{6}+3\geq 15$

Now Solving the above equation we get,

$\frac{x}{6}+3\geq 15\\\\\frac{x}{6}\geq 15-3\\\\\frac{x}{6}\geq 12\\\\x\geq 12\times6\\x\geq 72$

Hence the number is $x\geq 72$

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Suppose the vertex of a parabola is in the first quadrant and the parabola opens upwards. What can be determined about the value

schepotkina [342]

A parabola is the graph of a quadratic function,

that is the graph of $f(x)=a x^{2} +bx+c$ , where a is not 0.

from a, b and c we can derive the following informations about the shape of a parabola:

if a>0, the parabola opens upwards.
if a<0, the parabola opens downwards.

Consider the discriminant $D= b^{2} -4ac$

If D>0, the parabola intersects the x-axis at 2 points.
If D=0, the parabola intersects the x-axis at 1 point.
If D<0, the parabola does not intersect the x axis.

"<span>the vertex of a parabola is in the first quadrant and the parabola opens upwards.</span>"

the vertex is in the first quadrant means that the vertex is above the x-axis, and it opens upwards, so the parabola does not intersect the x-axis.

This means that:

Answer: a>0, the discriminant D<0

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3 years ago