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3 years ago

Help me please. 30 points :)

Mathematics

1 answer:

Nataly [62]3 years ago

3 0

$\frac{(5 \: - \: 8x)}{( \sqrt{5 \: - \: 8x} )} \: = \: \sqrt{5 \: - \: 8x}$
For the result to be Real,
$5 \: - \: 8x \: \geqslant \: 0$
$8x \: \leqslant \: 5$
$x \: \leqslant \: \frac{5}{8}$
$( \frac{(5 - 8x)}{( \sqrt{5 - 8x} )} ) \: \times \: (\frac{ \sqrt{5 - 8x} }{ \sqrt{5 - 8x} } ) \: = \: \frac{ {(5 \: - \: 8x)}^{ \frac{3}{2} } }{(5 \: - \: 8x)}$
Hence,
$\frac{{(5 \: - \: 8x)}^{ \frac{3}{2} } }{(5 \: - \: 8x)}$
is the required form.

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10 – 7x = 2 - 8x help :)

Rudik [331]

10-7x=2-8x

We move all terms to the left:

10-7x-(2-8x)=0

We add all the numbers together, and all the variables

-7x-(-8x+2)+10=0

We get rid of parentheses

-7x+8x-2+10=0

We add all the numbers together, and all the variables

x+8=0

We move all terms containing x to the left, all other terms to the right

x=-8

4 0

3 years ago

Read 2 more answers

Given f(x) = 70 + 11x, find x when f(x) =158

Mumz [18]

Answer:

$\huge \boxed{x = 8}$

Step-by-step explanation:

f(x) = 70 + 11x

To find the value of x when f(x) =158 , equate f(x) to 158

We have

$70 + 11x = 158 \\ 11x = 158 - 70 \\ 11x = 88$

Divide both sides by 11

$\frac{11x}{11} = \frac{88}{11} \\$

We have the final answer as

Hope this helps you

5 0

2 years ago

A survey is given to a class, asking about each person's favorite season of

lina2011 [118]

5/10 and 1/2 as they are the same.
Because there are 100 pupils in total.
10 choose summer and 40 choose fall, totalling 50 students out of 100.
=5/10 and 1/2

4 0

2 years ago

Plz help Jessica received scores of 86, 88, 92, and 90 on her first four tests in

Ierofanga [76]

To find the average you have to add 86, 88, 92, and 90 together and divide it by four.

86+88+92+90= 356
356/4= 89

ANSWER= 89

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2 years ago

Which pair of points forms a vertical line segment that is 4 units long?

uysha [10]

<span>In a Cartesian coordinate system, a vertical line segment always is parallel to the y-axis, so we have this coordinate system in the figure below. We need to find a pair of points that is 4 units long.

So, this pair of points are in the general forms as follow:

</span> $P_{1}( x_{1}, y_{1})$
$P_{2}( x_{2}, y_{2})$
<span>
Given that the straight line is vertical, then:

</span> $x_{1}=x_{2}$
<span>
Then the point 2 is modified as:

</span> $P_{2}( x_{1}, y_{2})$ <span>

We need to find a point which is 4 units long, so:

</span> $d = y_{2} - y_{1} = 4$
∴ $y_{2} = 4+ y_{1}$

So, we can find infinite points given a value of $y_{1}$ , therefore if:

$y_{1} = 2$ then:

∴ $y_{2} = 6$

Thus, if $x_{1} = 1$ then a pair of points are:

$P_{1}(1,2)$
$P_{2}(1,6)$

6 0

2 years ago