The volume of the solid of revolution is approximately 37439.394 cubic units.
<h3>
How to find the solid of revolution enclosed by two functions</h3>
Let be
and
, whose points of intersection are
,
, respectively. The formula for the solid of revolution generated about the y-axis is:
(1)
Now we proceed to solve the integral: 
(2)

![V = 6\pi \left[(y-1)\cdot \ln y\right]\right|_{1}^{e^{35/6}}](https://tex.z-dn.net/?f=V%20%3D%206%5Cpi%20%5Cleft%5B%28y-1%29%5Ccdot%20%5Cln%20y%5Cright%5D%5Cright%7C_%7B1%7D%5E%7Be%5E%7B35%2F6%7D%7D)
![V = 6\pi \cdot \left[(e^{35/6}-1)\cdot \left(\frac{35}{6} \right)-(1-1)\cdot 0\right]](https://tex.z-dn.net/?f=V%20%3D%206%5Cpi%20%5Ccdot%20%5Cleft%5B%28e%5E%7B35%2F6%7D-1%29%5Ccdot%20%5Cleft%28%5Cfrac%7B35%7D%7B6%7D%20%5Cright%29-%281-1%29%5Ccdot%200%5Cright%5D)


The volume of the solid of revolution is approximately 37439.394 cubic units. 
To learn more on solids of revolution, we kindly invite to check this verified question: brainly.com/question/338504
Answer:
Step-by-step explanation:
D
125/27 , or 4 & 25/27 , or 4.62963