Ask question

Ask question

All categories

3 years ago

11

Help me please. 30 points :)

1 answer:

Nataly [62]3 years ago

3 0

$\frac{(5 \: - \: 8x)}{( \sqrt{5 \: - \: 8x} )} \: = \: \sqrt{5 \: - \: 8x}$
For the result to be Real,
$5 \: - \: 8x \: \geqslant \: 0$
$8x \: \leqslant \: 5$
$x \: \leqslant \: \frac{5}{8}$
$( \frac{(5 - 8x)}{( \sqrt{5 - 8x} )} ) \: \times \: (\frac{ \sqrt{5 - 8x} }{ \sqrt{5 - 8x} } ) \: = \: \frac{ {(5 \: - \: 8x)}^{ \frac{3}{2} } }{(5 \: - \: 8x)}$
Hence,
$\frac{{(5 \: - \: 8x)}^{ \frac{3}{2} } }{(5 \: - \: 8x)}$
is the required form.

You might be interested in

Let S denote the plane region bounded by the following curves:

oee [108]

The volume of the solid of revolution is approximately 37439.394 cubic units.

<h3>How to find the solid of revolution enclosed by two functions</h3>

Let be $f(x) = e^{\frac{x}{6} }$ and $g(x) = e^{\frac{35}{6} }$ , whose points of intersection are $(x_{1},y_{1}) =(0,1)$ , $(x_{2}, y_{2}) = (35, e^{35/6})$ , respectively. The formula for the solid of revolution generated about the y-axis is:

$V = \pi \int\limits^{e^{35/6}}_{1} {f(y)} \, dy$ (1)

Now we proceed to solve the integral: $f(y) = 6\cdot \ln y$

$V = \pi \int\limits^{e^{35/6}}_{1} {6\cdot \ln y} \, dy$ (2)

$V = 6\pi \int\limits^{e^{35/6}}_{1} {\ln y} \, dy$

$V = 6\pi \left[(y-1)\cdot \ln y\right]\right|_{1}^{e^{35/6}}$

$V = 6\pi \cdot \left[(e^{35/6}-1)\cdot \left(\frac{35}{6} \right)-(1-1)\cdot 0\right]$

$V = 35\pi\cdot (e^{35/6}-1)$

$V \approx 37439.392$

The volume of the solid of revolution is approximately 37439.394 cubic units. $\blacksquare$

To learn more on solids of revolution, we kindly invite to check this verified question: brainly.com/question/338504

8 0

1 year ago

What is sqrt{4} times sqrt{4}

Lera25 [3.4K]

Answer:

Step-by-step explanation:

D

7 0

2 years ago

Read 2 more answers

The graph of an equation has a minimum y value of 12. This minimum occurs at an x value of 3. What is true of the graph of the e

Vika [28.1K]

Answer:

the answer is D

Step-by-step explanation:

7 0

2 years ago

Rewrite the following without an exponent

Leokris [45]

125/27 , or 4 & 25/27 , or 4.62963

7 0

2 years ago

Solve the inequality, if possible. If the inequality has no solution, write no solution. If the solutions are all real numbers,

Alina [70]

$7 - 6b \leq 19 - 7 \\ \\ -6b \leq 12 \\ \\ b \geq \frac{12}{-6} \\ \\ b \geq - \frac{12}{6} \\ \\ b \geq -2 \\ \\ Answer: b \geq -2$

6 0

3 years ago