Question

A fish is hooked on a line that is wound around the spool of a fishing reel. The reel has a mass of 652 g and a diameter of 10 cm. After 5 seconds, the reel is spinning with an angular velocity of 306 rad/s Assuming that the fish was pulling on the line with a constant force, what was the magnitude of this force?

Answer 1

The magnitude of the force exerted by the fish is 3,052.5 N.

The given parameters;

• mass of the reel, m = 652 g = 0.652 kg

• diameter of the reel, d = 10 cm

• radius of the reel, r= 5 cm = 0.05 m

• time of motion, t = 5 s

• angular speed of the reel, ω = 306 rad/s

According to Newton's third law, the force exerted by the reel is equal in magnitude to the force fish exerted on the reel.

The centripetal force of the reel = force exerted by the fish

$F_c = m\omega^2 r\\\\F_c = 0.652 \times (306)^2 \times 0.05\\\\F_c = 3,052.5 \ N$

Thus, the magnitude of the force exerted by the fish is 3,052.5 N.

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