Explanation:
As we know that the maximum of thermal energy will be converted into mechanical energy.( The thermal energy will be given to us by engine.)
But the total thermal energy will not be converted into the mechanical energy, there will be some lost of energy. The lost of mechanical energy will be in multiple forms. 2 of them are
1.Heat : The mechanical energy heats up the engine and then it will lost some energy.
2.Noise : Some energy also lost in the sound or the noise comes out from the engine. It will consume some energy.
Also, the engine never be 100% efficient some amount of energy lost in environment also.
<h3><u>Answer</u>;</h3>
= F0 L ( 1 - 1/e )
<h3><u>Explanation;</u></h3>
Work done is given as the product of force and distance.
In this case;
Work done = ∫︎ F(x) dx
= F0 ∫︎ e^(-x/L) dx
= F0 [ -L e^(-x/L) ] between 0 and L
= F0 L ( 1 - 1/e )
The chemical reaction that would represent the combustion of methane would be CH4 + 2O2 = CO2 + 2H2O. Combustion reactions are reactions which involves a substance burning in oxygen.
Answer: h = 0.52m
Explanation:
Using the equation of out flow;
A1 × V1 = A2 ×V2
Where A1 = area of the first nozzle
A2 = area of the second nozzle
V1= velocity of flow out from the first nozzle
V2 = velocity of flow out from 2nd nozzle
But AV= area of nozzle × velocity of water = volume of water per second(m³/s).
Now we can set A×V = Area of nozzle × height of rise.
Henceb A1× h1 = A2 × h2 ( note the time cancel on both sides)
D1 = 20mm= 0.02m; h1 = 0.13m
D2 = 10mm = 0.01m; h2= ?
h2 = π(D1/2)²× h1 /π(D2/2)²
h2 = (0.02/2)² × 0.13/(0.01/2)²
= (0.01)² ×0.13 /(0.005)²
= 1.3 × 10^-5/(5 × 10^-3)²
= 1.3 × 10^-5/25 × 10^-6
= (1.3/25) 10^-5 × 10^6
= 0.052× 10
= 0.52m
Explanation:
(a) The net force in the y direction is the sum of the individual forces. Taking up to be +y:
∑F = Lift − Weight
∑F = 100,000 N − 75,000 N
∑F = 25,000 N
(b) Since the net force is not 0, the forces are unbalanced.
(c) Since the lift is greater than the weight, the plane will rise.
(d) The net force in the x direction is the sum of the individual forces. Taking forward to be +x:
∑F = Thrust − Drag
∑F = 200,000 N − 23,000 N
∑F = 177,000 N
(e) Since the net force is not 0, the forces are unbalanced.
(f) Since the thrust is greater than the drag, the plane will accelerate.
