Given,
- HK is the perpendicular bisector of GJ. So, <u>GK = KJ</u>.
- GK = 2x + 10
- KJ = 3x - 15
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Find KJ .
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First find the value of x
Now, find the value of KJ.
-> The value of KJ is <u>6</u><u>0</u><u>.</u>
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Hope it helps.
RainbowSalt2222
Answer: 3.16
The first point, T = (x1,y1), and the second point, U = (x2,y2). Can be approximated as 3.16,so the distance between the two points is 3.16 units.
The surface area of a sphere is:
A=4πr^2, if r=12 and π is approximated as 3.14 then
A≈4(3.14)(12^2)
A≈4(3.14)(144)
A≈576(3.14)
A≈1808.64 cm^2
y= 2*x / x+3 that is my answer
Answer:
Variance = 1,227.27
Standard deviation = 35.03
Step-by-step explanation:
To calculate these, we use the following formulas:
Mean = (sum of the values) / n
Variance = ((Σ(x - mean)^2) / (n - 1)
Standard deviation = Variance^0.5
Where;
n = number of values = 20
x = each value
Therefore, we have:
Sum of the values = 29 + 32 + 36 + 40 + 58 + 67 + 68 + 69 + 76 + 86 + 87 + 95 + 96 + 96 + 99 + 106 + 112 + 127 + 145 + 150 = 1,674
Mean = 1,674 / 20 = 83.70
Variance = ((29-83.70)^2 + (32-83.70)^2 + (36-83.70)^2 + (40-83.70)^2 + (58-83.70)^2 + (67-83.70)^2 + (68-83.70)^2 + (69-83.70)^2 + (76-83.70)^2 + (86-83.70)^2 + (87-83.70)^2 + (95-83.70)^2 + (96-83.70)^2 + (96-83.70)^2 + (99-83.70)^2 + (106-83.70)^2 + (112-83.70)^2 + (127-83.70)^2 + (145-83.70)^2 + (150-83.70)^2) / (20 - 1) = 23,318.20 / 19 = 1,227.27
Standard deviation = 1,227.27^0.5 = 35.03
