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aalyn [17]
3 years ago
12

Help me out pleaseee

Mathematics
1 answer:
Kay [80]3 years ago
4 0
Please repost a clear picture so I can help, Thanks.
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suppose a parabola has an axis of symmetry at x=-2, a maximum height of 8, passes through the point (-6, 2). Wrire the equation
Virty [35]

Answer:

y = -3/8(x + 2)^2 + 8

Step-by-step explanation:

vertex form is

y = a(x - b)^2 + c     where a is a constant and (b,c) is the vertex.

The maximum is at (-2, 8)  because x 8 = height and x =-2 is equn. of symmetry

So here we have

y = a(x - (-2))^2 + 8

y = a(x + 2)^2 + 8

Now at the point (-6, 2):

2 = a(-6+2)^2 + 8

2 = 16a + 8

16a = -6

1 = -3/8.

So our equation is y = 3/8(x + 2)^2 + 8

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3 years ago
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Dmitrij [34]

Answer:

12:4

Step-by-step explanation:

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On Saturday afternoon, Armand sent m text messages each hour for 5 hours, and Tyrone sent p text messages each hour for 4 hours.
iren2701 [21]

Answer:

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2 years ago
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Find the measure of the indicated angle to the nearest degree
Alisiya [41]

Answer:

The answer to your question is below

Step-by-step explanation:

14) sin Ф = 32/33

    sin Ф = 0.9697

        Ф = 75.86°

15) sin Ф = 16/36

     sin Ф = 0.444

          Ф = 26.39°

16) sin Ф = 29/36

     sin Ф = 0.806

          Ф = 53.66°

17) cos Ф = 11/34

    cos Ф = 0.324

          Ф = 71.12°

18) sin Ф = 21/40

     sin Ф = 0.525

           Ф = 31.67°

19) cos Ф = 6/14

     cos Ф = 0.429

          Ф = 64.62°

20) cos Ф = 38/39

      cos Ф = 0.974

            Ф = 13°

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3 years ago
How many doughnuts are in 1/3 dozen? Please help meeee!!!!
Eva8 [605]
There are 4 doughnuts in 1/3 of a dozen
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