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GarryVolchara [31]
3 years ago
6

Hii Help plzz anyone!!

Mathematics
2 answers:
natka813 [3]3 years ago
7 0

Answer:

It's just addition and subtraction.

Step-by-step explanation:

1. $65,000

2. 66,000

3. 114,000

GaryK [48]3 years ago
6 0

Answer:

i hope it's help you

Step-by-step explanation:

1. $65,000

2. 66,000

3. 114,000

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If the AREA of the rectangle at the right is 22 3/4 square inches, what is the width of the rectangle?
sergejj [24]

Answer:

3.25 or 3 1/4 inches

Step-by-step explanation:

A = lw

22.75 = 7w

w = 3.25 which is 3 1/4

6 0
3 years ago
Pleasee mwa mwa mwa help me
sammy [17]

Answer: About (-2.414, 0) and (0.414, 0)

Step-by-step explanation:

       Let us graph the equation given and see what the x-intercepts are. These are points where the line intercepts the x-axis. <em>See attached</em>.

       This means our x-intercepts are at about (-2.414, 0) and (0.414, 0).

                        These are also equal to -1-\sqrt{2} and  -1+\sqrt{2}

8 0
2 years ago
Read 2 more answers
Find the equation of the line passing through point (4,2) and perpendicular to AB
Setler [38]

Answer:

a. -⅓

b. 3

c. y = 3x - 10

Step-by-step explanation:

a. Gradient of line AB:

A(1, 3), B(7, 1)

Gradient = \frac{y_2 - y_1}{x_2 - x_1} = \frac{1 - 3}{7 - 1} = \frac{-2}{6} = -\frac{1}{3}

Gradient (m) = -⅓

b. The of the line that is perpendicular to line AB would be the negative reciprocal of the gradient of line AB.

Thus, the negative reciprocal of -⅓ = 3

Gradient of the line perpendicular to line AB = 3

c. Equation of the line that passes through (4, 2) and is perpendicular to line AB:

We can write the equation using the point-slope form equation, y - b = m(x - a), where,

(a, b) represents a point on the line, and,

m = gradient/slope

We know that the gradient/slope (m) = 3

Also, a point, (a, b) = (4, 2).

Therefore, substitute a = 4, b = 2, and m = 3 into y - b = m(x - a)

Thus:

y - 2 = 3(x - 4)

y - 2 = 3x - 12

Add 2 to both sides

y = 3x - 12 + 2

y = 3x - 10

5 0
3 years ago
Find the distance between the two points rounding to the nearest tenth (if necessary).
Virty [35]

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{3}~,~\stackrel{y_1}{6})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{9})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{(1-3)^2+(9-6)^2}\implies d=\sqrt{(-2)^2+3^2} \\\\\\ d=\sqrt{13}\implies d\approx 3.6056\implies \stackrel{\textit{rounded up}}{d=3.6}

4 0
3 years ago
Let x represent the larger number4x+(x-2)^2=16
12345 [234]

I have no clue I just need the points have a good day tho :)

5 0
2 years ago
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