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morpeh [17]
3 years ago
8

Find Each Product Simplify ( x ^ 2 + 9 ) ( x + 3 ) ( x - 3) HELP ME PLEASE!

Mathematics
1 answer:
Kisachek [45]3 years ago
6 0
(x^2+9)(x+3)(x-3)=(x^2+9)(x^2-9)=x^4-81
Have a nice day!!! ^^
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Kirk bought songs for his MP3 player. He needed 6 more songs to have a total of 100. Write an integer to represent how many more
Anarel [89]
This is very easy to solve once you understanding writing equations. In this case, we could do n+6=100 because we know that the number of songs he has now (n) plus 6 will equal 100. Below is a solution for this equation.

n+6=100
   -6     -6
n=94

After solving our equation, we know that Kirk has 94 songs.
3 0
3 years ago
What are the solutions to the equation?
Tcecarenko [31]

Answer:

x = -4 ±3

x = -7,-1

Step-by-step explanation:

x^2 + 8x     = -7

1/2 B ^ 2 = 16

x^2 + 8x  + 16    = 16 -7

(x + 4) ^2 = 9

x + 4 = ±3

x = -4 ±3

x = -7,-1

5 0
3 years ago
The sides of a square field are 28 meters. A sprinkler in the center of the field sprays a circular area with a diameter that co
Stella [2.4K]
If a field is 900 meters squared and one side is twice as big as the other how big is each side
6 0
3 years ago
Multiply both equations by a constant
tiny-mole [99]

Answer:

(- \frac{1}{3}, \frac{3}{4} )

Step-by-step explanation:

9x + 8y = 3 → (1)

6x - 12y = - 11 → (2)

Multiplying (1) by 12 and (2) by 8 and adding will eliminate the y- term

108x + 96y = 36 → (3)

48x - 96y = - 88 → (4)

Add (3) and (4) term by term to eliminate y

156x = - 52 ( divide both sides by 156 )

x = \frac{-52}{156} = - \frac{1}{3}

Substitute this value into either of the 2 equations and solve for y

Substituting into (1)

9(- \frac{1}{3} ) + 8y = 3

- 3 + 8y = 3 ( add 3 to both sides )

8y = 6 ( divide both sides by 8 )

y = \frac{6}{8} = \frac{3}{4}

solution is (- \frac{1}{3}, \frac{3}{4} )

6 0
3 years ago
Johnny was able to drive an average of 29 miles per hour faster on his car after the traffic cleared. He drove 30 miles in traff
Fantom [35]

Answer:

15 mph

Step-by-step explanation:

Before traffic cleared:

distance = 30 miles

average speed = s

time = t

d = st

30 = st

After traffic cleared:

distance = 176 miles

average speed = s + 29

time = 6 - t

d = st

176 = (s + 29)(6 - t)

30 = st

s = 30/t

176 = (30/t + 29)(6 - t)

176t = (30 + 29t)(6 - t)

176t = 180 - 30t + 174t - 29t^2

29t^2 + 32t - 180 = 0

(29t + 90)(t - 2) = 0

t = -90/29 or t = 2

Time must be a positive number, so we discard the solution t = -90/29.

t = 2

30 = st

30 = s * 2

s = 15

Answer: 15 mph

3 0
3 years ago
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