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enot [183]
2 years ago
15

Find a parametric representation of the solution set of the linear equation. (Enter your answer as a comma-separated list of equ

ations. Use s and t as your parameters.)
x + y + z = 8
Mathematics
1 answer:
STALIN [3.7K]2 years ago
8 0

Answer:

  x = s, y = t, z = 8 -s -t

Step-by-step explanation:

It can work reasonably well to let s and t represent any of a pair of the variables. In the answer above, we have used x=s, y=t.

You could get more elaborate if you want:

  x = 4-s, y = 4-t, z = s+t

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ILL GIVE BRAINLEST, Find the value of x.
natali 33 [55]

Answer:

x=6, y=128

 

set 5x+16 = 7x+4

-2x=-12

x=6

plug x into equation= 46

180-46=134

y+6=134

y=128

3 0
3 years ago
Read 2 more answers
How do I evaluate the expression -(p+q)2 /(-6) for p=2 andq=4
Dimas [21]
Plug in the values of p and q where you see them in the equation:

-(2+4)2 / (-6) - Distribute the -1 
(-2-4)2 / (-6) -  Distribute the 2
(-4-8) / (-6) - Subtract what's inside the parenthesis
(-12) / (-6) - Divide
The answer is 2
3 0
3 years ago
What is the difference between these two expressions?
mariarad [96]

Answer:

The answer is:

Option 4; (14+ 9) 4 is twice as much as(14 + 9) 2

Thanks

5 0
3 years ago
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a 12- inch ruler is duvided into 3 parts. the large part is 3 times longer than the small. the meddium part is times longer than
damaskus [11]

Answer:

2 inches

Step-by-step explanation:

x= smallest

3x=largest

2x=medium

x+3x+2x=12

6x=12

x=2

so smallest is 2

largest is 6 (3x)

medium is 4 (2x)

2+6+4=12

6 0
3 years ago
Which statement is true about the flight of 2 rockets?
umka21 [38]

Answer:

  The first rocket, g(x), reached its maximum height before the second rocket, h(x).

Step-by-step explanation:

Each equation is in vertex form, so we can read the vertex of the rocket's path from the equation.

  y = a(x -h)^2 +k . . . . . . has vertex (h, k)

__

g(x) has vertex (time, max height) = (4, 170).

h(x) has vertex (time, max height) = (5, 170).

The rockets have the same maximum height (170), but the first rocket, g(x), reaches that height in 4 seconds, one second sooner than the second rocket, h(x).

The first rocket, g(x), reached its maximum height before the second rocket, h(x).

7 0
3 years ago
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