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katovenus [111]
2 years ago
13

Anyone know the answer good 15 points ???

Mathematics
1 answer:
Klio2033 [76]2 years ago
5 0

Answer:

When solving for a variable, you undo all operations done to that variable.

In the equation 6x - 3 = -51 we see on the left-hand side that the variable x is being multiplied by 6 and subtracted 3 times.

We can reverse the subtraction operation by using the inverse of subtraction.

Which is the addition operation. If we add 3 to the left-hand side, the -3 term will disappear.

But wait! Anything we do on one side we must do also on the opposite side.

6x - 3 + 3 = -51 + 3

6x             = -48

Now how can we undo the multiplication operation done to x?

We can use division. It will make the 6 coefficient disappear!

6x / 6 = -48/6

x = -8

<h3>So, x is equal to -8. (C) </h3>

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if the product of 4 and a number is decreased by 12, the result is twice the opposite of the number. Find the number. EXPLAIN PL
ELEN [110]
Answer:  The number is:  "2 " .
__________________________________________
Explanation:
__________________________________________
Write the expression; which is an equation, as follows:
__________________________________________
     " 4x <span>− 12 = 2(-x) " ;  in which "x" represents "the number for which we shall                                       solve" .
___________________________________________
Note:  

If the "number" = "x" ;  the "opposite of the number"  =  " -x " ;
</span>___________________________________________
Rewrite as:  " 4x <span>− 12 = -2x " ;
</span>_____________________________________________
     →  Add "12" ; & add "2x" ; to EACH SIDE of the equation:

                      4x − 12 + 12 + 2x = -2x + 12 + 2x ;

           to get:    6x  = 12  ;
____________________________________________________
 Now, divide each side of the equation by "6" ; 
     to isolate "x" on one side of the equation; & to solve for "x" ;
____________________________________________________
                         6x / 6  =  12 / 6 ;

                    to get:    x = 2 .
____________________________________________________
Answer:  The number is:  "2 " .
____________________________________________________
Let us check our answer, by plugging in "2" for "x" in our original equation:
_____________________________________________________
        →   " 4x − 12 = 2(-x) " ;

  Let us plug in "2" for "x" ; to see if the equation holds true; that is; if both side of the equation are equal; when "x = 2" ;

        →   " 4(2) − 12 = ?  2(-2) ?? 

        →    8 − 12 = ?  -4 ? ;
 
        →    -4 = ? -4 ??  Yes!
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6 0
3 years ago
Student scored in the 83rd
melamori03 [73]

Answer:b

Step-by-step explanation:

5 0
2 years ago
Use Euler's method with step size 0.2 to estimate y(1), where y(x) is the solution of the initial-value problem y' = x2y − 1 2 y
irina [24]

Answer:

Therefore the value of y(1)= 0.9152.

Step-by-step explanation:

According to the Euler's method

y(x+h)≈ y(x) + hy'(x) ....(1)

Given that y(0) =3 and step size (h) = 0.2.

y'(x)= x^2y(x)-\frac12y^2(x)

Putting the value of y'(x) in equation (1)

y(x+h)\approx y(x) +h(x^2y(x)-\frac12y^2(x))

Substituting x =0 and h= 0.2

y(0+0.2)\approx y(0)+0.2[0\times y(0)-\frac12 (y(0))^2]

\Rightarrow y(0.2)\approx 3+0.2[-\frac12 \times3]    [∵ y(0) =3 ]

\Rightarrow y(0.2)\approx 2.7

Substituting x =0.2 and h= 0.2

y(0.2+0.2)\approx y(0.2)+0.2[(0.2)^2\times y(0.2)-\frac12 (y(0.2))^2]

\Rightarrow y(0.4)\approx  2.7+0.2[(0.2)^2\times 2.7- \frac12(2.7)^2]

\Rightarrow y(0.4)\approx 1.9926

Substituting x =0.4 and h= 0.2

y(0.4+0.2)\approx y(0.4)+0.2[(0.4)^2\times y(0.4)-\frac12 (y(0.4))^2]

\Rightarrow y(0.6)\approx  1.9926+0.2[(0.4)^2\times 1.9926- \frac12(1.9926)^2]

\Rightarrow y(0.6)\approx 1.6593

Substituting x =0.6 and h= 0.2

y(0.6+0.2)\approx y(0.6)+0.2[(0.6)^2\times y(0.6)-\frac12 (y(0.6))^2]

\Rightarrow y(0.8)\approx  1.6593+0.2[(0.6)^2\times 1.6593- \frac12(1.6593)^2]

\Rightarrow y(0.6)\approx 0.8800

Substituting x =0.8 and h= 0.2

y(0.8+0.2)\approx y(0.8)+0.2[(0.8)^2\times y(0.8)-\frac12 (y(0.8))^2]

\Rightarrow y(1.0)\approx  0.8800+0.2[(0.8)^2\times 0.8800- \frac12(0.8800)^2]

\Rightarrow y(1.0)\approx 0.9152

Therefore the value of y(1)= 0.9152.

4 0
3 years ago
Find the given term 11, -33,99 9th term
kvv77 [185]
Assuming the sequence goes on like this 11,-33,99,-297,891,...,
its general formula is a_n=-11\cdot(-1)^n\cdot3^{n-1}

So, the 9th term is
a_9=-11\cdot(-1)^9\cdot3^{9-1}=-11\cdot(-1)\cdot6561=72171
5 0
2 years ago
A square centimeter is the area covered by a square whose sides are 1 meter long.
eduard
The correct answer is:  [B]:  "False" .
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  <u>Note</u>:  A "square centimeter" is the area covered by a square whose sides are:
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  <u>Note</u>:  A "square meter" is the area covered by a square whose sides are:
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3 years ago
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