(3y^7)^3 3^3*y^(7*3)
------------ = ------------------
9y^9 9*y^9
(3y^7)^3 3^3*y^(7*3) 27*y^21 (mult. together the exponents 3 and 7)
------------ = ------------------ = --------------
9y^9 9*y^9 9*y^9
That 27/9 reduces to 3. y^(21) / y^9 reduces to y^12.
Thus, we obtain 3*y^12 (answer)
Please do the next one, asking questions if need be, and showing your work.
Answer:
There are 8 tens and 2 ones
Step-by-step explanation:
Hope this helps
Answer:
3:1
Step-by-step explanation:
F(x)=IxI-5
when you shift it up, add the units to the end of y=IxI
when you shift it down, subtract the units to the end of y=IxI
Answer:
765
Step-by-step explanation:
