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Brilliant_brown [7]
3 years ago
11

I need help with this question

Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
6 0

The distance between Hadley and Greenville is 16 miles.

29-13=16

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What is 3kg 296g+5kg 326g
Alex_Xolod [135]
you would combine the numbers with the same letters(like terms) you would end up with 622g+8kg
8 0
3 years ago
Write each number in scientific notation. 1. 14,700
grigory [225]
1.) 1.47 x 10^4 is the correct answer
8 0
3 years ago
Simplify the following v^4*v^5*v
Hunter-Best [27]

Answer:

v^10

Step-by-step explanation:

For this, we need to understand one important rule of exponents.  For powers of like bases, you add the exponents when they are being multiplied.  With this in mind let's continue.

In this problem, the base is v, each multiplied with different powers.  So:

v^4 * v^5 * v = v^(4+5+1) = v^10

So the solution will be v^10.

An additional example would be 2^2 * 2^3.

For this we know it would be 2^2 * 2^3 = 2^(2+3) = 2^5 = 32.

We can verify by simply doing 2 * 2 * 2 * 2 *  2 = 32.  Note both are 32, and this example shows the usefulness of exponent rules.

Hope this helps.  Cheers.

3 0
3 years ago
Read 2 more answers
The diameters of ball bearings are distributed normally. The mean diameter is 106 millimeters and the standard deviation is 4 mi
Assoli18 [71]

Answer:

Probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.

Step-by-step explanation:

We are given that the diameters of ball bearings are distributed normally. The mean diameter is 106 millimeters and the standard deviation is 4 millimeters.

<em>Firstly, Let X = diameters of ball bearings</em>

The z score probability distribution for is given by;

          Z = \frac{ X - \mu}{\sigma} ~ N(0,1)

where, \mu = mean diameter = 106 millimeters

            \sigma = standard deviation = 4 millimeter

Probability that the diameter of a selected bearing is greater than 111 millimeters is given by = P(X > 111 millimeters)

    P(X > 111) = P( \frac{ X - \mu}{\sigma} > \frac{111-106}{4} ) = P(Z > 1.25) = 1 - P(Z \leq 1.25)

                                                  = 1 - 0.89435 = 0.1056

Therefore, probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.

4 0
3 years ago
What’s the answer and how do I solve it?
Dimas [21]

Answer:

x= -1, x=3

Step-by-step explanation:

The “zeros” of a quadratic function are where the parabola intersects the x axis. In that graph the parabola touches x=-1 and x=-3. Therefore that is the answer.

8 0
3 years ago
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