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2 years ago

Solve for n. 2n - 3 5 = = 5 Enter your answer in the box. n =

Mathematics

2 answers:

padilas [110]2 years ago

8 0

Answer:

Step-by-step explanation:

2n-35=5

2n=5+35=40

n=40/2=20

Zina [86]2 years ago

4 0

Answer:

$2n - 35 = 5 \\ 2n = 5 + 35 \\ 2n = 40 \\ n = 40 \div 2 \\ n = 20$

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Elia is training for her first marathon. she currently runs 10 mi. per week, and wants to increase her mileage by 2 mi. every we

Semenov [28]

Answer: Required expression is given by

$y=8+2x$

Step-by-step explanation:

Since we have given that

Number of miles per week Elia is training for her first marathon = 10 miles

According to question, we have given that she wants to increase her mileage by 2 miles every week.

so, Equation becomes

10,12,14,16..........

Let the number of weeks be x

Since it forms an Arithmetic sequence,

As we know the formula for nth term :

$a_x=10+(x-1)2\\\\y=10+2x-2\\\\y=8+2x$

So, our required expression will be

$y=8+2x$

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2 years ago

Read 2 more answers

How do you write 79% as a fraction, mixed number, or whole number in simplest form?

wolverine [178]

As a fraction, it would be 79/100

4 0

3 years ago

Read 2 more answers

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d1i1m1o1n [39]

Well, the first dot is the known as the Minimum. Then, the second dot is the 1st Quartile. The dot in the middle of the box with the line through it is the median (2nd Quartile). Then the last dot forming the box is the 3rd Quartile. And the final dot is the 4th Quartile (Also known as the Maximum). In this case, it is asking about the Median...which would be 15.5. Hope this helped!

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3 years ago

Use the chain rule to find dw/dt. w = ln x2 + y2 + z2 , x = 7 sin(t), y = 9 cos(t), z = 6 tan(t)

DENIUS [597]

By the chain rule,

$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\partial w}{\partial x}\dfrac{\mathrm dx}{\mathrm dt}+\dfrac{\partial w}{\partial y}\dfrac{\mathrm dy}{\mathrm dt}+\dfrac{\partial w}{\partial z}\dfrac{\mathrm dz}{\mathrm dt}$

We have

$\dfrac{\partial w}{\partial x}=\dfrac{2x}{x^2+y^2+z^2}$
$\dfrac{\partial w}{\partial y}=\dfrac{2y}{x^2+y^2+z^2}$
$\dfrac{\partial w}{\partial z}=\dfrac{2z}{x^2+y^2+z^2}$

$\dfrac{\mathrm dx}{\mathrm dt}=7\cos t$
$\dfrac{\mathrm dy}{\mathrm dt}=-9\sin t$
$\dfrac{\mathrm dz}{\mathrm dt}=6\sec^2t$

So we have

$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac2{x^2+y^2+z^2}\left(7x\cos t-9y\sin t+6z\sec^2t\right)$
$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{2\left(49\sin t\cos t-81\cos t\sin t+36\tan t\sec^2t\right)}{49\sin^2t+81\cos^2t+36\tan^2t}$
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3 years ago

Solve the system: (MAFS.912-A-REI.3.6)

faust18 [17]

Step-by-step explanation:

$4x + 7y = 41 \\ 4 \times ( - 7) + 7 \times ( - 16) = 41$

7 0

2 years ago