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Softa [21]
3 years ago
7

Suppose the odds against winning the lottery as 48,000,000 to 1. What is the probability of the event of winning the lottery giv

en these odds?
Mathematics
1 answer:
kupik [55]3 years ago
8 0

The probability according to the given scenario will be "\frac{1}{48,000,001}".

According to the question:

  • The odds against winning the lottery are 48,000,000 to 1.
  • Favorable outcome = 1

→ The total outcome will be:

= 48,000,000 +1

= 48,000,001

As we know,

→ P(E) = \frac{Favorable \ outcomes}{Total \ outcomes}

By putting the values, we get

→           =\frac{1}{48,000,001}

Thus the above response is right.

Learn more about Probability here:

brainly.com/question/15739211

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\qquad \qquad \huge \pink {\sf{☁Answer☁}} \\  \\

\large \purple { \rm{Let's  \: solve→}} \\

\rm{3(2x-5)=4x+33} \\  \\  \rm {solving \: bracket} \\  \\ \rm{6x - 15= 4x + 33} \\  \\ \rm{arranging \: terms} \\  \\  \rm{6x - 4x = 33  +  15} \\  \\  \rm{2x = 48} \\  \\  \rm{x =  \frac{48}{2} } \\  \\  \rm{x =  \cancel \frac{48}{2} } \\  \\  \rm{x = 24}

\purple{\rule{15mm}{2.9pt}} \red{\rule18mm{2.5pt}} \orange{ \rule18mm{2.5pt}}

\sf{\:мѕнαcкεя\: ♪...}

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