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Softa [21]
2 years ago
7

Suppose the odds against winning the lottery as 48,000,000 to 1. What is the probability of the event of winning the lottery giv

en these odds?
Mathematics
1 answer:
kupik [55]2 years ago
8 0

The probability according to the given scenario will be "\frac{1}{48,000,001}".

According to the question:

  • The odds against winning the lottery are 48,000,000 to 1.
  • Favorable outcome = 1

→ The total outcome will be:

= 48,000,000 +1

= 48,000,001

As we know,

→ P(E) = \frac{Favorable \ outcomes}{Total \ outcomes}

By putting the values, we get

→           =\frac{1}{48,000,001}

Thus the above response is right.

Learn more about Probability here:

brainly.com/question/15739211

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