I believe its C because that is slope intercept form and any points that follow that formula is a solution to that equation. And there is more than 1 solution to this equation.
Answer:
B
Step-by-step explanation:
First put it in standard form:
<span>x^2 −14x -15 =0
a =1 b =-14 c=-15
Then use the quadratic formula:
x = [-b +-sq root (b^2 - 4ac)] / 2a
x = [--14 +- sq root (14^2 -4*1*-15] / 2*1
x = [14 +-sq root (196 +60)] / 2
</span><span>x = [14 +- 16] / 2
x1 = 15
x2 = -1
</span>
The factored form of the equation that has the zeros 4 and -7 is y = ( x - 4)( x + 7 ).
<h3>What is the factored form of an equation that has the zeros or roots 4 and -7?</h3>
Roots are simply the points where the graph intercepts with the x-axis. ( y = 0 )
That is, y = 0 the roots
Given the roots of the equation;
Now, at x = 4,
x = 4
x - 4 = 0
y = ( x - 4)
Also, at x = -7,
x = -7
x - ( - 7 ) = 0
x + 7 = 0
y = ( x + 7 )
Hence; for the equation with the given roots; 4 and -7 will be;
y = ( x - 4)( x + 7 ).
The factored form of the equation that has the zeros 4 and -7 is y = ( x - 4)( x + 7 ).
Learn more about roots of quadratic equation here: brainly.com/question/26926523
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