0.5 inches a month.
I believe you subtract 13 1/4 by 10 3/4 = 2 1/2.
Then you divide by 5.
Answer:
<em>Two possible answers below</em>
Step-by-step explanation:
<u>Probability and Sets</u>
We are given two sets: Students that play basketball and students that play baseball.
It's given there are 29 students in certain Algebra 2 class, 10 of which don't play any of the mentioned sports.
This leaves only 29-10=19 players of either baseball, basketball, or both sports. If one student is randomly selected, then the propability that they play basketball or baseball is:

P = 0.66
Note: if we are to calculate the probability to choose one student who plays only one of the sports, then we proceed as follows:
We also know 7 students play basketball and 14 play baseball. Since 14+7 =21, the difference of 21-19=2 students corresponds to those who play both sports.
Thus, there 19-2=17 students who play only one of the sports. The probability is:

P = 0.59
Answer: e = 17.8
Step-by-step explanation: 14.6 + 3.2
Answer:
B
Step-by-step explanation:
They are increasing by 1 vertically. Hope this helps!! :)
first qn
4/36=1/9
total no. of ways to roll a dice=36
no. of ways to produce 7=3
(1+6=7, 2+5=7, 3+4=7)
no. of ways to produce 11=1
(5+6=11)
there are 4 ways in total. 4/36 simplify it to be 1/9
second qn im not sure but i think its
1/9 x 50 = 50/9 = 5 x (5/9)
round it off to the smaller whole no. which is 5 so i think its 5 times in 50 trials