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almond37 [142]
3 years ago
15

One side of a square has endpoints (4.7) and (-3,5). What is the perimeter of the square?

Mathematics
1 answer:
Goryan [66]3 years ago
4 0

Answer:

= 4√53 units

that is option(a)

Step-by-step explanation:

all sides of the square are of the same length

so if we get the length if this side, we can calculate its perimeter

there's this formula,

<u>side length between two points, let's say A(x, y) and B(p, q), is equal to </u>

\mathsf{ \sqrt{ {(x - p)}^{2} +  {(y - q)}^{2}  } }

so here we go,

the same points A and B here are

(4, 7) and (-3, 5)

therefore, side length :-

= \mathsf{ \sqrt{( {7 - 5})^{2}  +  {(4 - ( - 3))}^{2} } }

=  \mathsf{ \sqrt{ {2}^{2} +  {7}^{2}  } }

=  \mathsf{  \sqrt{4 + 49}  }

=   \mathsf{\sqrt{53} }

the side length comes out to be <u>√(</u><u>53</u><u>) </u>

now perimeter of a square is

4 × side length

= 4√53 units

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Do the product 40x500 and 40x600 have the same number of zeros
VARVARA [1.3K]

No they do not have the same number of zeroes

Although the 2 products do seem like they might have the same number of zeroes, 40 x 500 and 40 x 600

both have 3 zeroes before multiplying

if we take the first 2 digits of the 2 numbers being multiplied to get an idea of the answer

 if we take 40 x 500 - 4 x 5 = 20

then theres an extra zero added

but if we take 40 x 600 - 4 x 6 = 24

no extra zeroes added to this


so if we finally look at the answers

40 x 500 = 20 000

40 x 600 = 24 000

20000 has 4 zeroes and 24000 has 3 zeroes


so the answer is no they dont have the same number of zeroes

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3 years ago
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What is the length of the cylinder's height? Please help​
raketka [301]

Answer:

  • Height = <u>9</u><u> </u>cm which means <u>Option </u><u>C </u>is the answer

Step-by-step explanation:

In the question we are given ,

  • Volume of cylinder = <u>2</u><u>2</u><u>5</u><u>π</u><u> </u><u>cm³</u>

  • Radius of cylinder = <u>5 cm</u>

And , we have to find the <u>height</u><u> of</u><u> </u><u>cylinder</u><u> </u>.

We know that ,

\longrightarrow \pink{ \boxed{Volume \:  of \:  Cylinder = \pi r {}^{2}h  }} \longleftarrow

Our solution starts from here :

\longmapsto \: \pi \: r {}^{2} h = 225\pi

<u>Step </u><u>1</u><u> </u><u>:</u> Cancelling π with π :

\longmapsto \:  \cancel{\pi} \: r {}^{2} h = 225 \cancel{\pi}

<u>Step </u><u>2</u><u> </u><u>:</u> Substituting value of radius which is 5 cm in the formula :

\longmapsto \: (5) {}^{2}  \times h = 225

\longmapsto \: 25h = 225

<u>Step </u><u>3 </u><u>:</u> Transposing 25 to right hand side :

\longmapsto \: h =  \frac{225}{25}

<u>Step </u><u>4</u><u> </u><u>:</u> Cancelling 225 by 25 :

\longmapsto \:   \red{\boxed{h = 9 \: cm}}

  • <u>Henceforth</u><u> </u><u>,</u><u> </u><u>height</u><u> </u><u>of </u><u>cylinder</u><u> is</u><u> </u><u>9</u><u> </u><u>cm</u>

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Fittoniya [83]
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Alchen [17]

Answer:

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Step-by-step explanation:

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12²+35²=c² so

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Answer:

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Step-by-step explanation:

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