Answer:
to the nearest tenth would be, 9.9
Step-by-step explanation:
Use distance formula:
(-3-4)^2 + (8-1)^2 all under square root.
49 + 49

Which simplifies to 7
Hope this helps,
Feel free to mark this brainliest! :)
Answer:
90
Step-by-step explanation:
I do not know if this is true or not but i am pretty sure this is perimeter
All triangles sides have to add up to 180
1. add up 25 and 65
2. 180-90=90
Then i think your answer is 90
<u>Please do not give me hate if i did this wrong</u>
Hi there,
Question: Need to Solve for y.
8×+9y=-5
-8×-9y=5
Answer:
8 × +9y = -5
Solve your equation in steps:
(8)(9)y = -5
Step 1: Simplify both sides of the equation
72y = -5
Step 2: Divide both sides by 72
72y/72 = -5/72y
Then when your done, you get your answer y= -5/72
Answer:
-8 × -9y = 5
Solve your equation in steps:
((-8)(-9))(y) = 5
Step 1: Simplify both sides of the equation.
72y = 5
Step 2: Divide both sides by 72.
72y/72 = 5/72
Then when your done, you get your answer y= 5/72
So here is the answers for both math problems.
8 × +9y = -5 is y= -5/72
-8 × -9y = 5 is y= 5/72
Hope this helps!
Answer:yes he has enough
Step-by-step explanation:
Markdown: 25% of 180. 25%x180 0.25x180=$45. The markdown is $45 sale price: 180-45=$135. Sales tax:8.25%x135 0.0825x135=11.1375(not rounded)=11.40(rounded) Add: 135+11.1375 to get 146.1375(not rounded)= 146.40(rounded)
9514 1404 393
Answer:
(√5)/2
Step-by-step explanation:
Of the several ways I can think of to do this, using a graphing calculator is about the easiest. It shows the minimum to be ...
f(1) = √1.25 = (√5)/2
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Using the distance formula, you have ...
f(x) = √((x -(-2))² +((x² +2)-5/2)²)
f(x) = √(x² +4x +4 +x⁴ -x² +1/4) = √(x⁴ +4x +17/4)
The minimum is found where the derivative is zero.
f'(x) = (2x³ +2)/√(x⁴ +4x +17/4) = 0
x³ = -1 . . . . . f'(x) is zero when the numerator is zero
x = -1 . . . . . cube root
Then the minimum value of f(x) is ...
f(-1) = √(x⁴ +4x +17/4) = √((-1)⁴ +4(-1) +17/4) = √(1 -4 +17/4) = √(5/4)
f(-1) = (√5)/2 . . . . minimum value of f(x)
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The graph shows f²(x) in red and its minimum of 1.25 = 5/4. The curve (x, x²+2) and the point (-2, 5/2) are also shown, for reference. (The slope of the curve at x=-1 is -2, and the normal to the curve at that point has slope 1/2. The normal goes through the point (-2, 5/2), consistent with f(x) being a minimum at x=-1.)