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lianna [129]
2 years ago
12

During a rain storm a pail collects 1/3 of an inch of water in 5/6 of a minute at what rate is the pail collecting water

Mathematics
1 answer:
melomori [17]2 years ago
5 0

Answer:

2/5.

Step-by-step explanation:

.

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Translation four units down and two units right
bogdanovich [222]

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be more specific? what's your question?

Step-by-step explanation:

4 0
3 years ago
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a homeowner plans to hang wallpaper on one wall of a bedroom that is 10 feet long. if a strip of wallpaper is 20 inches wide and
love history [14]
1 ft = 12 inches....so 10 ft = (10 * 12) = 120 inches

each strip of wall paper is 20 inches...

so 120/20 = 6 strips of wall paper are required <==


4 0
3 years ago
The relationship between antioxidant food consumption per day in cups and the BMI of an individual is modeled by the following l
Katena32 [7]
This is in gradient intercept form (or slope intercept form)
y = mx + b
in this case y = -1.2x + 26
so m (the slope) = -1.2
and the y intercept = 26
I'm not sure what intercept they're asking for.
if you wanted to find the x intercept, just substitute.
y = 0 and find x.
8 0
3 years ago
Pleaseee Help URGENTTTT
Marizza181 [45]

Answer:

correct answer is b

Step-by-step explanation:

7 0
3 years ago
Find cotθ, cosθ, and secθ, where θ is the angle shown in the figure.
Darina [25.2K]

Answer:

\cos( \theta)  =  \frac{5}{8}  \\  {8}^{2}  =  {5}^{2}  +  {opp}^{2}  \\ {opp}^{2}  = 64 - 25 = 39 \\ opp =  \sqrt{39}  \\  \sin(\theta)  =  \frac{\sqrt{39}}{8}  \\  \tan(\theta)  =  \frac{ \sqrt{39} }{5}  \\  \cot(\theta)  =  \frac{1}{\tan(\theta)}  =  \frac{1}{\frac{ \sqrt{39} }{5}}  \\ \cot(\theta)  =  \frac{5}{ \sqrt{39} }  \\  \csc( \theta) =  \frac{1}{\sin(\theta)}  =  \frac{1}{\frac{\sqrt{39}}{8}}   \\ \csc( \theta) = \frac{8}{ \sqrt{39} }  \\  \sec( \theta) =  \frac{1}{\cos( \theta) }  =  \frac{1}{ \frac{5}{8} }  \\ \sec( \theta) =  \frac{8}{5}

5 0
2 years ago
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