Surface area is an important factor in limiting cell growth because
a. the cell can burst if the membrane becomes too large.
b. materials cannot enter the cell if the surface is too large.
c. the cell may become too large to take in enough food and to remove enough wastes.
d. waste products cannot leave the cell if the cell is too small.
Answer:
c. the cell may become too large to take in enough food and to remove enough wastes.
Explanation:
The exchange of substances with surroundings is done by cells by the process of diffusion. The rate of diffusion of substances requires the presence of a higher surface area than volume. As the cells become larger, their surface area is reduced with respect to the volume. Therefore, larger cells can not support the diffusion of substances in and out as required for its proper functioning. If cells are allowed to grow continuously, they will not be able to intake the requires materials such as food and to release the waste outside.
Answer:
Option b) waxes
Explanation:
because it is kind of liquids utilized in synthesis of rubber
Due to the high surface tension, the lungs remain crushed and you will not be able to breathe first.
During fertilization, the sperm and egg combine in one of the fallopian tubes to form a zygote. The zygote then descends the fallopian tube into a morula. Upon reaching the uterus, the morula becomes a blastocyst. The blastocyst then burrows into the inner wall of the uterus. This is a process called implantation.
The prenatal development process occurs in three major stages. The first two weeks after conception are called the germination period, the third to eighth weeks are called the fetal period, and the period from the ninth week to birth is called the fetal period.
Learn more about Fetus Developement here: brainly.com/question/1311741
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Answer:
b
Explanation:
the inner would have more heat bc it is surrounded
