Let . Then
for all
, so
is strictly increasing. As
,
, so
is bounded above by 1. This is to say,
and the integral of converges over the same domain, so this integral must also converge by comparison.
We have, by setting ,
Which explains whether or not the values in the table represent a direct variation?
1 answer:
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Answer:
Step-by-step explanation:
In right triangle XZW, the height WY is the geometric mean of segments ZY and XY.
Hence,
A vertical asymptote is a line that the graph of the function does not cross.
If:
+/- ∞
then the line x = a is a vertical asymptote.
For x = 0:
f ( 0 ) = 3 * cot 0 - 4 = ∞
For x = +/- 2 π :
f ( 2 π ) = 3 * cot π - 4 = - ∞
Answer:
A ) x = 0 and C ) x = +/- 2π
If:
then the line x = a is a vertical asymptote.
For x = 0:
f ( 0 ) = 3 * cot 0 - 4 = ∞
For x = +/- 2 π :
f ( 2 π ) = 3 * cot π - 4 = - ∞
Answer:
A ) x = 0 and C ) x = +/- 2π