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Sholpan [36]
3 years ago
7

Here’s another! Offering a brainliest! JUST FOR FUN +10points

Mathematics
2 answers:
Makovka662 [10]3 years ago
8 0
HMMmmmmmm my guess 27
Illusion [34]3 years ago
6 0

Answer:

Brainilist Lost all of mine     you have26?

Step-by-step explanation:

You might be interested in
If you can figure it out amazing!<br><br>find x​
mixer [17]
X + 17 = 3x -31 (opposite angles are equal)
x + 17 = 3x -31
31 +17 = 3x - x
48 = 2x
x = 24
4 0
3 years ago
Read 2 more answers
If h is a linear function with h(1) = 10 and h(3) = -6, what is h(5)?
Ghella [55]

Answer:

h(5) = - 22

Step-by-step explanation:

Given that h is a linear function say, h(x) = ax + b ......... (1)

Now, given that h(1) = 10 and h(3) = - 6  

Hence, we can write from equation (1), a(1) + b = 10, ⇒ a + b = 10 .......... (2)

And a(3) + b = - 6, ⇒ 3a + b = - 6 ........ (3)

Now, solving equations (2) and (3) we get (3a - a) = - 6 - 10

⇒ 2a = - 16

⇒ a = - 8

So, from equation (2), we get, b = 10 - a = 18  

Therefore, the linear function is

h(x) = - 8x + 18

Hence, h(5) = - 8(5) + 18 = - 22 (Answer)

5 0
4 years ago
What does A equal to
ruslelena [56]
Since you know that PQ=RQ, you have an equilateral triangle. This makes things very simple.
Angle R should be the same as angle P.
A triangle is equal to 180 degrees.
Add angles P and R. Subtract 180 from the answer you got. That will give you 2a. a divided by 2 will give you a.

Or, since there are two right triangles, you can add 47 and 90. Subtract 180 from that and you will get a.
5 0
3 years ago
Does anyone know how to solve this?
Charra [1.4K]

Answer:

\frac{\sqrt{2}}{2}

Step-by-step explanation:

This almost looks like the left hand side of the following identity:

\sin(A)\cos(B)-\sin(B)\cos(A)=\sin(A-B) .

Here are similar identities in the same category as the above:

\sin(A)\cos(B)+\sin(B)\cos(A)=\sin(A+B)

\cos(A)\cos(B)-\sin(A)\sin(B)=\cos(A+B)

\cos(A)\cos(B)+\sin(A)\sin(B)=\cos(A-B)

Things to notice: 90-76=14. and 90-59=31.

This means we will possibly want to use the following co-function identities:

\cos(90-A)=\sin(A)

\sin(90-A)=\cos(A)

So let's begin:

\sin(76)\cos(31)-\sin(14)\cos(59)

Applying the co-function identities:

\cos(14)\cos(31)-\sin(14)\sin(31)

Applying one of the difference identities above with cosine:

\cos(31+14)

\cos(45)

45 is a special angle so \cos(45) is something you find off most unit circles in any trigonometry class.

\cos(45)=\frac{\sqrt{2}}{2}

5 0
4 years ago
A circle has a circumference of 77cm. calculate the radius of the circle. (take TT=22/7​
Nina [5.8K]
Don’t u do like 77*r*d not sure
8 0
2 years ago
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