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masha68 [24]
2 years ago
10

Find a radius of a circle the length of which is 24π cm.

Mathematics
1 answer:
Juli2301 [7.4K]2 years ago
3 0

Answer:

12

Step-by-step explanation:

Length of a circle = circumference = 2πr = 24π

                                            Radius (r) = 24π/2π

                                                             = 12cm

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4<br> Om obtuse, scalene<br> Obright, scalene<br> Oc, right, isosceles<br> Od, right, equilateral
harina [27]

Answer:

B

Step-by-step explanation:

B. right, scalene

3 0
2 years ago
What is the equation of a line that contains point (2, -1) and is parallel to<br> y =<br> *x+3<br> ?
prohojiy [21]

Answer:

6 degrees

Step-by-step explanation:

8 0
3 years ago
Write and solve a proportion to answer the question. (Skills Review Handbook) 22. 30 is 15% of what number?
algol13

Answer:

The answer is 148.6666667

Step-by-step explanation:

1) Set a linear quation

\frac{22.30}{x}  =  \frac{15}{100}

2) Cross multiply

15x = 22.30 \times 100

3) Multiple the right side

15x = 2230

4) Divide both side by 15

\frac{15x}{15}  =  \frac{2230}{15}

5) Solve the linear equation

x = 148.6666667

3 0
2 years ago
Try to find x &amp; y. I need it so much please
kumpel [21]

Answer:

x = 3

y = 5

Step-by-step explanation:

Using theorem of similar triangles, we have,

(6 + x)/6 = (7 + 3.5)/7

(6 + x)/6 = 10.5/7

Cross multiply

7(6 + x) = 10.5(6)

42 + 7x = 63

7x = 63 - 42

7x = 21

x = 21/7

x = 3

Thus:

7.5/y = (7 + 3.5)/7

7.5/y = 10.5/7

Cross multiply

7.5*7 = 10.5*y

52.5 = 10.5*y

Divide both sides by 10.5

52.5/10.5 = y

y = 5

3 0
3 years ago
The perimeter of the rectangle is 22 meters, and the perimeter of the triangle is 12 meters. Find the dimensions of the rectangl
lianna [129]

Answer:

Length:8 m

Width:3 m

Step-by-step explanation:

<u><em>The complete question is</em></u>

If the perimeter of a rectangle is 22 meters, and the perimeter of a right triangle is 12 meters (the sides of the triangle are half the length of the rectangle, the width of the rectangle, and the hypotenuse is 5 meters). How do you solve for L and W, the dimensions of the rectangle.

step 1

<em>Perimeter of rectangle</em>

we know that

The perimeter of rectangle is equal to

P=2(L+W)

we have

P=22\ m

so

22=2(L+W)

Simplify

11=L+W -----> equation A

step 2

Perimeter of triangle

The perimeter of triangle is equal to

P=\frac{L}{2}+W+5

P=12\ m

so

12=\frac{L}{2}+W+5

Multiply by 2 both sides

24=L+2W+10

L+2W=14 ----> equation B

Solve the system of equations by graphing

Remember that the solution is the intersection point both graphs

using a graphing tool

The solution is the point (8,3)

see the attached figure

therefore

The dimensions of the rectangle are

Length:8 m

Width:3 m

3 0
3 years ago
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