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ludmilkaskok [199]
3 years ago
14

5<-3x+8 solve and graph the question

Mathematics
1 answer:
bearhunter [10]3 years ago
3 0

Answer:

x<1

Step-by-step explanation:

5<-3x+8 ⇒3x<8-5⇒3x<3⇒x<1

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Step-by-step explanation:

sory I ain't know

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What sample size should be used if we would like to estimate the mean age of the college students at a particular campus with 95
nevsk [136]

Answer: 12

Step-by-step explanation:

The formula to find the sample size is given by:-

n=(\dfrac{z_c\cdot \sigma}{E})^2 , where \sigma is the population standard deviation, z_c is the z-value for the (1-\alpha) confidence interval and E is the margin of error .

As per given , we have

Population standard deviation : \sigma=5.1

z-value for 95% confidence interval : z_c=1.960

Margin of error : E= 3

Then, the required minimum sample :-

n=(\dfrac{(1.96)\cdot (5.1)}{3})^2\\\\\Rightarrow\ n=(3.332)^2=11.102224\approx12

Hence, the required minimum sample size = 12

3 0
3 years ago
14 - 2x = 3(x - 2) what is the answer​
RSB [31]
The answer will be x=4
4 0
3 years ago
Two supplementary angles have measures (3X +14°) and (2X -9°) what are the measures of two angles
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The increasing cost of health care is an important issue today. Suppose that a random sample of 36 small companiesthat offer pai
garri49 [273]

Answer:

The 99% confidence interval is given by ($109.386;$138.613)

Step-by-step explanation:

1) Notation and definitions

n=36 represent the sample size

\bar X= 124 represent the sample mean  

s=32 represent the sample standard deviation

m represent the margin of error

Confidence =99% or 0.99

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

2) Calculate the critical value tc

In order to find the critical value is important to mention that we don't know about the population standard deviation, so on this case we need to use the t distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. The degrees of freedom are given by:  

df=n-1=36-1=35  

We can find the critical values in excel using the following formulas:  

"=T.INV(0.005,31)" for t_{\alpha/2}=-2.74  

"=T.INV(1-0.005,31)" for t_{1-\alpha/2}=2.74  

The critical value tc=\pm 2.74

3) Calculate the margin of error (m)

The margin of error for the sample mean is given by this formula:

m=t_c \frac{s}{\sqrt{n}}

m=2.74 \frac{32}{\sqrt{36}}=14.613

4) Calculate the confidence interval  

The interval for the mean is given by this formula:

\bar X \pm t_{c} \frac{s}{\sqrt{n}}

And calculating the limits we got:

124 - 2.74 \frac{32}{\sqrt{36}}=109.386

124 + 2.74 \frac{32}{\sqrt{36}}=138.613

The 99% confidence interval is given by ($109.386;$138.613)

4 0
3 years ago
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