We know that
see the attached figure to better understand the problem
sin x°=opposite ÷ <span>hypotenuse
cos x</span>°=adjacent ÷ hypotenuse
cosec x°=1/ sin x°-------> hypotenuse ÷ opposite
sec x°=1/ cos x°-------> hypotenuse ÷ adjacent
therefore
case A) <span>sec x° = opposite ÷ adjacent------------> is not correct
case B) </span>cosec x° = opposite ÷ adjacent ------------> is not correct
case C) cosec x° = hypotenuse ÷ opposite ------------> is correct
case D) sec x° = adjacent ÷ hypotenuse------------> is not correct
the answer is
the equation cosec x° = hypotenuse ÷ opposite is correct
Answer:
x^2+y^2+z^2-10x-6y-10z +50 =0
Step-by-step explanation:
Given that a sphere is contained in the first octant
Centre of the sphere is given as (5,3,5)
Since this is contained only in the first octant radius should be at most sufficient to touch any one of the three coordinate planes
When it touches we can get the maximum sphere
We find that y coordinate is the minimum of 3 thus radius can be atmost 3 so that then only it can touch y =0 plane i.e. zx plane without crossing to go to the other octants.
Hence radius =3
Equation of the sphere would be

500Answer:
600
Step-by-step explanation:
Answer:
$57.50
Step-by-step explanation:
find 10% of 50 first, which is 5, because 5 × 10 = 50, then add $10 to the $50 beacause 50 × 0.2 = 10, next, remove 5%, to do this divide 10% by 2 to get $2.50, 60 - 2.5 = 57.5