A part manufactured by plastic injection molding has a historical mean of 100 and a historical standard deviation of 8. Find the
1 answer:
Answer:
The probability of thickness exceeding 101 is 0.4483.
Step-by-step explanation:
Let <em>X</em> denote the thickness of the part manufactured by plastic injection molding.
Assume that <em>X</em> follows a normal distribution with mean, <em>μ</em> = 100 and standard deviation, <em>σ</em> = 8.
Compute the probability of thickness exceeding 101 as follows:
Thus, the probability of thickness exceeding 101 is 0.4483.
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Answer:
The correct option is the graph on the bottom right whose screen grab is attached (please find)
Step-by-step explanation:
The information given are;
The required model height for the designed clothes should be less than or equal to 5 feet 10 inches
The equation for the variance in height is of the straight line form;
y = m·x + c
Where x is the height in inches
Given that the maximum height allowable is 70 inches, when x = 0 we have;
y = m·0 + c = 70
Therefore, c = 70
Also when the variance = 0 the maximum height should be 70 which gives the x and y-intercepts as 70 and 70 respectively such that m = 1
The equation becomes;
y ≤ x + 70
Also when x > 70, we have y ≤ -x + 70
with a slope of -1
To graph an inequality, we shade the area of interest which in this case of ≤ is on the lower side of the solid line and the graph that can be used to determine the possible variance levels that would result in an acceptable height is the bottom right inequality graph.
Answer:
Step-by-step explanation:
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