A part manufactured by plastic injection molding has a historical mean of 100 and a historical standard deviation of 8. Find the
1 answer:
Answer:
The probability of thickness exceeding 101 is 0.4483.
Step-by-step explanation:
Let <em>X</em> denote the thickness of the part manufactured by plastic injection molding.
Assume that <em>X</em> follows a normal distribution with mean, <em>μ</em> = 100 and standard deviation, <em>σ</em> = 8.
Compute the probability of thickness exceeding 101 as follows:
Thus, the probability of thickness exceeding 101 is 0.4483.
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Answer:
42.43 ft
Step-by-step explanation:
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h² = p² + f² -2x p×f×cos45
h² = 43² + 60² - 2x (43)(60) x 0.7071
h² = 1849 + 3600 - 3648.636
h² = 1800.364
h = √1800.364
h = 42.43 feet
<h2>Answer:</h2>
The ratio of the area of region R to the area of region S is:
The sides of R are in the ratio : 2:3
Let the length of R be: 2x
and the width of R be: 3x
i.e. The perimeter of R is given by:
( Since, the perimeter of a rectangle with length L and breadth or width B is given by:
)
Hence, we get:
i.e.
Also, let " s " denote the side of the square region.
We know that the perimeter of a square with side " s " is given by:
Now, it is given that:
The perimeters of square region S and rectangular region R are equal.
i.e.
Now, we know that the area of a square is given by:
and
Hence, we get:
and
i.e.
Hence,
Ratio of the area of region R to the area of region S is: