28. Surface Area
This is some sort of house-like model so for every face we see there's a congruent one that's hidden. We'll just double the area we can see.
Area = 2 × ( [14×9 rectangle] + 2[15×9 rectangle]+[triangle base 14, height 6] )
Let's separate the area into the area of the front and the sides; the front will help us for problem 29.
Front = [14×9 rectangle] + [triangle base 14, height 6]
= 14×9 + (1/2)(14)(6) = 14(9 + 3) = 14×12 = 168 sq ft
OneSide = 2[15×9 rectangle] = 30×9 = 270 sq ft
Surface Area = 2(168 + 270) = 876 sq ft
Answer: D) 876 sq ft
29. Volume of an extruded shape is area of the base, here the front, times the height, here 15 feet.
Volume = 168 * 15 = 2520 cubic ft
Answer: D) 2520 cubic ft
The answer is c. 240π
V=πr² h/3 =π×6²× 20/3 ≈753.98224
Answer:
B. 1/3 or 33.3%
Step-by-step explanation:
<em>H-</em> 1 ,2 ,3, 4, 5, 6
<em>T-</em> 1, 2, 3, 4, 5, 6
Multiples of <em>3:</em> 3, 6, 9, 12, etc..
<em>2/6 simplified is 1/3 </em>
So, the probability that the penny will land on heads and the number cube will land on a multiple of 3, is 1/3 or 33.3%
<h3>
Answer: 11 cans</h3>
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Explanation:
SA = surface area of the sphere
SA = 4*pi*r^2
SA = 4*pi*8^2
SA = 804.247719
The surface area is roughly 804.247719 sq ft.
I used the calculator's stored version of pi to get the most accuracy possible.
Since 1 paint can covers 75 sq ft, divide that surface area over 75 to find out how many cans you need.
804.247719/75 = 10.72330292
Round up to the nearest integer to get 11
You'll have leftover paint, but it's better to go over the goal than come up short.
