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Art [367]
3 years ago
9

Simplify the expression: 8a + 9(7 + 10a)

Mathematics
1 answer:
Irina18 [472]3 years ago
3 0

Answer:

8a+9(7+10a)

8a+63+90a

8a+90a+63

98a+63.

Thank you.

BY GERALD GREAT.

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Is the m in mx+b=y the growth
Shalnov [3]

The "m" in y = mx + b is the <u>slope.</u>

It is the number of units a point goes up, down, left, or right each time. Making the line linear/straight.

m = \frac{rise}{run}

"rise" is the the number of units you go up(+) or down(-), "run" is the number of units you go to the right


For example, if your slope is:

\frac{1}{2}

You are going up 1 unit, and to the right 2 units


3 or \frac{3}{1}

You are going up 3 units, and to the right 1 unit


-\frac{1}{2}

You are going down one unit, and to the right 2 units


-3 or -\frac{3}{1}

You are going down 3 units, and to the right 1 unit

4 0
3 years ago
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gavmur [86]

Answer:

the 2:The constant of proportionality is the ratio between two directly proportional quantities. Two quantities are directly proportional when they increase and decrease at the same rate. 3

Step-by-step explanation:

40 to 8

Each pizza costs $8 and the delivery fee is $3.

5 0
3 years ago
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Julli [10]

Add dress and shoes together:

30 + 25 = 55

1/5 off means the total after discount would be 4/5 ( 1 - 1/5 = 4/5)

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7 0
3 years ago
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Find the value of the six trig functions given the triangle below.
Y_Kistochka [10]

\text{Here,}\\\\\text{Opposite side,}~ O = 2\\\\\text{Hypotenuse,}~ H   = \sqrt 5 \\\\\text{Adjacent side,}~ A = \sqrt{5-4} = \sqrt 1  =1  ~~ ;[\text{By using Pythagorean theorem}]\\\\\\\sin \theta = \dfrac{O}H = \dfrac 2{\sqrt 5}\\\\\\\cos \theta = \dfrac{A}{H} = \dfrac{1}{\sqrt 5} \\ \\\\ \tan \theta = \dfrac{O}{A} = \dfrac 21 = 2

csc \theta = \dfrac{1}{\sin \theta} = \dfrac{\sqrt 5}2\\\\\\\sec \theta = \dfrac{1}{\cos \theta} = \sqrt 5  \\\\\\\cot \theta = \dfrac 1{\tan \theta} = \dfrac 12

5 0
3 years ago
What is the simplified form of the following expression? 10abc^2 sqrt 49a^2b^2c^2
Elodia [21]
10abc^2\sqrt{49a^2b^2c^2}=70a^2b^2c^3 

_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ 

10abc^2\sqrt{49a^2b^2c^2} 

\sqrt{49a^2b^2c^2}=7abc 

7\cdot \:10aabbc^2c 

70aabbc^2c 

70a^2bbc^2c 

70a^2b^2c^2c 

70a^2b^2c^3
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3 years ago
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