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IrinaK [193]
3 years ago
11

Simplify:(4x2 - 2x) - (-5x2 - 8x). yall dont gotta simplify this im just bored

Mathematics
1 answer:
jeka57 [31]3 years ago
4 0

Answer:

wsp?

Step-by-step explanation:

9x^2 + 6x

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Find the range for the given domain: {-2, -1, and 0} and the function is y= 3x^2
likoan [24]

Answer:

  {0, 3, 12}

Step-by-step explanation:

Put the domain values in the function and evaluate. The result is the range values.

  y = 3{-2, -1, 0}^2 = 3{4, 1, 0} = {12, 3, 0}

For the given domain, the range is {0, 3, 12}.

_____

<em>Additional comment</em>

Neither the domain nor range values need to be put in any particular order. However, it is often convenient for them to be arranged from least to greatest.

6 0
3 years ago
How many mg is .625 ml???
Harlamova29_29 [7]
0.625000 is the correct answer
8 0
3 years ago
Triangle ABC has vertices at A(−1 , 2), B(4, 2), and C(3, −1). Classify the triangle according to the side lengths.
Orlov [11]

Answer:

B) Isosceles

Step-by-step explanation:

The given triangle has vertices at A(-1,2), B(4,2) and C(3,-1).

We must first determine the length of the sides of the triangle, before we can classify it.

We apply the distance formula to find length of the sides.

|AB|=\sqrt{(4--1)^2+(2-2)^2}

\Rightarrow |AB|=\sqrt{(4+1)^2+(2-2)^2}

\Rightarrow |AB|=\sqrt{5^2+(0)^2}

\Rightarrow |AB|=\sqrt{25}

\Rightarrow |AB|=5 units.

The length of side BC

|BC|=\sqrt{(3-4)^2+(-1-2)^2}

\Rightarrow |BC|=\sqrt{(-1)^2+(-3)^2}

\Rightarrow |BC|=\sqrt{1+9}

\Rightarrow |BC|=\sqrt{10}

The length of side AC

|AC|=\sqrt{(3--1)^2+(-1-2)^2}

We simplify to obtain;

|AC|=\sqrt{(3+1)^2+(-3)^2}

\Rightarrow |AC|=\sqrt{(4)^2+(-3)^2}

|AC|=\sqrt{16+9}

|AC|=\sqrt{25}

|AC|=5\:units

Since |AC|=5\:units=|AB|, the given triangle is an isosceles triangle.

The correct answer is

6 0
3 years ago
Read 2 more answers
A line segment whose endpoints are (2,6) and (8,y) is perpendicular to a line whose slope is -4. What is the value of y?
Mariulka [41]
If the line segment is perpendicular to a line with the slope of -4, that means the line segment has a slope of 1/4.

First let's make an equation for the line segment using the slope of 1/4 and the point at (2,6) to find the final piece, the y-intercept

y = mx + b
6 = 1/4(2) + b
6 = 2/4 + b
24/4 = 2/4 + b
22/4 = b

y = 1/4 x + 22/4
6 = 1/4(2) + 22/4
6 = 2/4 + 22/4
6 = 24/4
6 = 6 <-- proves that this equation is correct

Now you may plug in the x to find y. ( 8 , y )
y = 1/4(8) + 22/4
y = 8/4 + 22/4
y = 30/4 = 15/2 = 7.5
4 0
3 years ago
The volume of a right circular cone varies jointly as the altitude and the square of the radius of the base. If the volume of th
Tresset [83]

Answer:13.5 inches

Step-by-step explanation:

Here, the volume of a right circular cone varies jointly as the altitude and the square of the radius of the base

So our equation for volume becomes

V = c*h*r^2

where 'h' is altitude and 'r' is radius of base and 'c' is constant

Putting the value of V,h,r,

we get,

154 = c*12*3.5*3.5

c = 22/21

Now we have volume = 77 cu and radius of the base =7/3, so putting the values we get,

77 = 22/21*h*7/3*7/3

or, h= 13.5

Hope it helps!!!

6 0
3 years ago
Read 2 more answers
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