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Aleonysh [2.5K]
3 years ago
5

How to solve number 1

Mathematics
1 answer:
Mkey [24]3 years ago
4 0
You obviously solve whatever the problem is
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What does x equal in -2(4-3x)-6x=10
Natali [406]

Answer:

No solution

Step-by-step explanation:

-2(4-3x)-6x = 10

-8 + 6x - 6x = 10

-8 = 10

there is no solution because -8 cannot = 10

7 0
3 years ago
Fine the sum of the first 8 terms of the arithmetic series 2+7+12+...
ss7ja [257]

Answer:

156

Step-by-step explanation:

s8 = n/2 [2t + (n-1)(d)]

= 8/2 [2(2) + (8-1)(5)]

= 4 [4 + (7)(5)]

= 4 (4 + 35)

= 4 (39)

= 156

4 0
3 years ago
Area of square tile, math question
Inessa05 [86]

Answer:

Answer: √49

___________

√49 = 7

Step-by-step explanation:

The area of a square is equal to the square of its side or the product of its side and its side.

A = s², because the sides of a square are congruent.

5 0
4 years ago
A closed cylindrical vessel contains a fluid at a 5MPa pressure. The cylinder, which has an outside diameter of 2500mm and a wal
Julli [10]

Answer:

1) Increase in the diameter equals 3.5 mm

2) Increase in the length equals 0.0003724L_{i} where L_{i} is the initial length of the vessel.

Step-by-step explanation:

The diametric strain in the vessel is given by

\epsilon_{D} =\epsilon_{diam}-\nu \epsilon _{axial}

We have

\epsilon _{diam}=\frac{\sigma _{hoop}}{E}\\\\\sigma _{hoop}=\frac{\Delta P\times D}{2t}\\\\\therefore \epsilon _{diam}=\frac{\Delta P\times D}{2t\times E}

Applying values we get

\therefore \epsilon _{diam}=\frac{5\times 10^{6}\times 2.5}{2\times 20\times 10^{-3}\times 193\times 10^{9}}\\\\\therefore \epsilon _{diam}=\frac{5}{3088}

Similarly axial strain is given by

\epsilon _{diam}=\frac{\sigma _{axial}}{E}

\sigma _{axial}=\frac{\Delta P\times D}{4t}\\\\\therefore \epsilon _{axial}=\frac{\Delta P\times D}{4t\times E}

Applying values we get

\therefore \epsilon _{axial}=\frac{5\times 10^{6}\times 2.5}{4\times 20\times 10^{-3}\times 193\times 10^{9}}\\\\\therefore \epsilon _{diam}=\frac{2.5}{3088}

Hence The effect of axial strain along the diameter is given by

-\nu \epsilon _{axial}

Applying values we get

-\nu \epsilon _{axial}=-0.27\times \frac{2.5}{3088}=-0.0002185

hence

\epsilon _{D} =\frac{5}{3088}-0.0002185\\\\\epsilon =0.00140

Now by definition of strain we have

\epsilon _{D} =\frac{D_{f}-D_{i}}{D_{i}}\\\\\therefore D_{f}=D_{i}+\epsilon D_{i}\\\\D_{f}=2.5+0.0014\times 2.5\\\\\therefore D_{f}=2503.5mm

Increase in the diameter is thus 3.5 mm

Using the same procedure for axial strain we have

\epsilon_{axial} =\epsilon_{axial}-\nu \epsilon _{diam}

Applying values we get

\epsilon_{axial} =\frac{2.5}{3088}-0.27\times \frac{5}{3088}

\epsilon_{axial} =0.0003724

Now by definition of strain we have

\epsilon _{axial} =\frac{L_{f}-L_{i}}{L_{i}}\\\\\therefore \Delta L=0.0003724L_{i}

where L_{i} is the initial length of the cylinder.

6 0
4 years ago
The side length of Tom's square garden was 12 m. He used of the garden for growing roses. What area of his garden was used for g
miv72 [106K]

Answer:

144

Step-by-step explanation:

Because area is side times side, and it was a square garden, so that means that there is the same side length on each side so just 12 x 12 is 144.

6 0
3 years ago
Read 2 more answers
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