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Aleonysh [2.5K]

3 years ago

5

How to solve number 1

1 answer:

Mkey [24]3 years ago

4 0

You obviously solve whatever the problem is

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2 years ago

Two fractions one positive one negative whose product is 5/8

Ray Of Light [21]

-10/8 and + 15/8. Those should work.

3 0

3 years ago

Anyone have any idea? i dont have any idea

ladessa [460]

Answer:

$\tt f(x)=2x^2+20x-10$

let y=f(x)

$\tt y=2x^2+20x-10$

$\tt 2x^2+10x=y+10$

$\tt x^2+10x=\frac{1}{2} y+5$

$\tt x^2+10x+25=\frac{1}{2} y+30$

$\tt (x+5)^2=\frac{1}{2} (y+60)$

$\tt 2(x+5)^2=f(x)+60$

$\boxed{\tt f(x)=2(x+5)^2-60}$

Hope it helps! :)

8 0

2 years ago