All categories

3 years ago

How to solve number 1

Mathematics

1 answer:

Mkey [24]3 years ago

4 0

You obviously solve whatever the problem is

You might be interested in

How do you simplify without using a calculator (-5)(7)+4×5

Evgesh-ka [11]

Answer:

-15 Is the answer

Step-by-step explanation:

(-5)(7)+4×5

= -15

(-5)(7) + 4×5 = -15/1 = -15

Multiple: -5 * 7 = -35

Multiple: 4 * 5 = 20

Add: the result of step No. 1 + the result of step No. 2 = -35 + 20 = -15

Hope this helps.

7 0

2 years ago

HELP!!!! Additive Identify property stuff!!!!

bearhunter [10]

Answer:

i am pretty sure it is F

Step-by-step explanation:

8 0

3 years ago

Which relationships describe the angle pair x° and 157º?

katrin2010 [14]

Adjacent and supplementary :))

4 0

2 years ago

Read 2 more answers

The first quartile of a data set is 23

LenaWriter [7]

Answer:

The first quartile of a data set is 23 the median is 30 the third quartile is 33 and an outlier is 50. Which of these data values would be represented by a point in a modified box plot?

Answer is 50

7 0

2 years ago

he number of retro portable CD players you are prepared to supply to a retail outlet every week is given by the formula q = 0.1p

AlladinOne [14]

Answer:

Supply will decrease at the rate of 29 CDs per week.

Step-by-step explanation:

The number of retro portable CD players prepared to supply to a retail outlet every week is represented by the formula

q = 0.1p² + 9p

Here p = price offered

price it offers decreases at a rate of $1 per week.

In other words, $\frac{dp}{dt}=(-$1) per week$

Now we differentiate the given equation

$\frac{dq}{dt}=\frac{d}{dt}(0.1p^{2}+9p )$

$\frac{dq}{dt}=[0.1(2p)+9]\frac{dp}{dt}$

Since, $\frac{dp}{dt}=(-$1) per week$

$\frac{dq}{dt}=(-1)[0.1(2p)+9]$

For p = 100,

$\frac{dq}{dt}=(-1)[(0.1\times 200)+9]$

= (-1)[20+9]

= -29

Therefore, $\frac{dq}{dt}=(-29)$

Supply will decrease at the rate the rate of 29 CDs per week.

3 0

3 years ago