15/100 = x/82. I think that could be a proportion.
Answer:
x (8, 0) y (0, -4) I think
Answer:
Step-by-step explanation:
The average is 81 a low B, but if you throw out the low score it rises to 88.8, a high B.
I would use the median 88, 89 since it is higher and is a more accurate representation of the majority of the class
The answer is
A(m) = 12 + 2m
B(m) = 10 + 3m
m - the number of months
F(m) - growth in a function of months m
Species A is 12 cm tall, so the number 12 is independent on a number of months. But it <span>grows 2 cm per month. This means that in m months it will grow 2 * m. So, its function is: A(m) = 12 + 2m
Similarly, s</span>pecies B is 10 cm tall, so the number 10 is independent on a number of months. But it grows 3 cm per month. This means that in m months it will grow 3 * m. So, its function is: B(m) = 10 + 3m
Answer:
The fraction of horses that are Morgan's=17/20
Step-by-step explanation:
Step 1: Determine fraction for each breed
Arabians=1/4
Thoroughbreds=2/5
Morgan's=unknown
Step 2: Express each breed as a fraction of the total
Number of Arabians=fraction of Arabians×total number of horses
Let total number of horses be x
Arabians=(1/4)×x=1/4 x
Thoroughbreds=(2/5)×x=2/5 x
Morgans's=m
Step 3: Calculate fraction of Morgans
Total number of horses=Arabians+Thoroughbreds+Morgans
x=(1/4)x+(2/5)x+m
solve for m;
m=x-(1/4)x-(2/5)x
m=x-3/20x
m=17/20 x
The fraction of horses that are Morgan's=17/20
